Question

one number is 6 times a first number. a third number is 100 more than the first number. if the sum of the three numbers is 316, find the numbers

Answer 1

Answer:

27, 162, and 127

Step-by-step explanation:

take x plus 6 times the first number x and the third number is (x+100). put it together and you get x+6x+(x+100)=316 combine like terms to get 8x (x+6x+x)+100=316, subtract 100 to both sides. 8x=216 divide by 8 and you get x=27. that's the first number, multiply it by 6 to get 162 which is the second and the third is 27+100 which is 127