Answer:
y - 1 = 5(x - 5)
Step-by-step explanation:
Given the following data;
Points (x, y) = (5, 1)
Slope = ?
From the question, the value of the slope is missing. Hence, let's assume a value of 5.
Mathematically, the equation of a straight line is given by the formula;
y = mx + c
Where;
m is the slope.
x and y are the points
c is the intercept.
To find the equation of line, we would use the following formula;
y - y1 = m(x - x1)
Substituting into the formula, we have;
y - 1 = 5(x - 5)
y - 1 = 5x - 25
y = 5x - 25 + 1
y = 5x - 24 = mx + c
Answer:
y-intercept = -4
Step-by-step explanation:
equation of a line: y=mx+b
two points given are (5, -6.5) and (-12, 2)
first we can easily find value of m or the slope, by using the slope formula. the value of m=-0.5.
formua to find m:
= -0.5
to find the value of b (the y-intercept), we need to plug in a y and x value, we are given 2 ordered pairs, you can use either one and plug x-value in for x and the y-value in for y.
if i plug in (5, -6.5), my equation looks like this: -6.5=5(-0.5)+b
then you just solve for b and it turns out to be -4.
Answer: subtraction property.
Step-by-step explanation:
The point of intersection you are concerned with is the left-most of those of the graphed lines. Thus you want the two equatons that both have x-intercepts that are negative. Since the x-coefficient is positive in every case, this will mean the right-side constants of these equations both need to be negative. The appropriate choice is ...
A. 4x - 5y = -5 and 3x + 10y = -20
(x-4)(x-4)
5(x^2-8x+16)=60
5x^2-40x+80=60
5x^2-40x+20=0
5(x^2-8x+4)
something like this