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irakobra [83]
3 years ago
7

Find the perimeter of the quadrant whose radius is 28cm​

Mathematics
2 answers:
fiasKO [112]3 years ago
6 0

Answer:

\huge\boxed{Perimeter = 99.98\ cm}

Step-by-step explanation:

Quadrant is one - fourth of a circle

Perimeter of quadrant = \frac{2\pi r }{4} + 2r

Where r = 28 cm

=> P = \frac{2(3.14)(28)}{4} + 2(28)

=> P = (3.14)(14) + 56

=> P = 43.98 + 56

=> P = 99.98 cm

Alenkasestr [34]3 years ago
5 0

Answer:

\huge \boxed{\mathrm{99.98 \ cm}}

Step-by-step explanation:

A quadrant is quarter of a circle.

The perimeter of a quarter of a circle is \frac{2\pi r}{4} +2r.

The radius r is 28 cm.

\frac{2\pi (28)}{4} +2(28)= 99.982297...

The perimeter of the quadrant with radius 28 cm is approximately 99.98 cm.

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Step-by-step explanation:

Given

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Required

Get equivalent expression using completing the square

<em>Follow these steps:</em>

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<em />

Add to both sides of the equation

y^2 - 12y + (\frac{-12}{2})^2= -27 + (\frac{-12}{2})^2

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y^2 - 12y + 36= -27 + 36

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y^2 - 6y - 6y + 36= 9

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also, remember pythagorean rule, sin^2(x)+cos^2(x)=1

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using pythagrean identity

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cos(Θ)=+/-3/5

in 1st quadrant, cos is positive

cos(Θ)=3/5


so sin(Θ+x)=sin(Θ)cos(x)+cos(Θ)sin(x)

sin(Θ+x)=(4/5)(-5/13)+(3/5)(12/13)

sin(Θ+x)=16/65



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