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sp2606 [1]
3 years ago
13

A horizontal pull P pulls two wagons over a horizontal frictionless

Physics
1 answer:
nalin [4]3 years ago
3 0
<span>where u is in radians. The linear velocity of the point is tangent to the circle; the point’s linear speed v is given by v vr (radian measure), (10-18) wherev is the angular speed (in radians per second) of the body. The linear acceleration of the point has both tangential and radial components.The tangential component is at ar (radian measure), (10-22) where a is the magnitude of the angular acceleration (in radians per second-squared) of the body.The radial component of is (radian measure). (10-23) If the point moves in uniform circular motion, the period T of the motion for the point and the body is (radian measure).</span>
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4
tensa zangetsu [6.8K]

Answer:

C. amount of charge on the source charge.

Explanation:

Electric field lines can be defined as a graphical representation of the vector field or electric field.

Basically, it was first introduced by Michael Faraday and it is typically a curve drawn to the tangent of a point is in the direction of the net field acting on each point.

The number, or density, of field lines on a source charge indicate the amount of charge on the source charge. Therefore, the density of field lines on a source charge is directly proportional to quantity of charge on the source.

8 0
3 years ago
What is the momentum of a 0.1-kg mass moving with a speed of 5 m/s
Andrej [43]
This question is wrong because in momontum we will write acceleration instead of speed.     suppose acceleration is 5m/s2 then 
 P= ma 
                then put values
   
4 0
3 years ago
A race car accelerates from 0 m/s ro 30 m/s with a displacement of 45 what is it acceleration
Minchanka [31]
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6 0
4 years ago
A rising pendulum bob gains _____ energy.
puteri [66]

Answer:

B. Kinetic energy.............

4 0
3 years ago
Read 2 more answers
Estimate the volume of a typical house (2050 feet squared in size and 10 feet tall) answer in units of meters squared
Aloiza [94]

Answer:

Volume = 6248.48 m^{3}

Explanation:

Given:

The area of the house A = 2050\ ft^{2}

The height of the house h=10\ ft

We need to find the volume of a typical house.

Solution:

We find the volume of the house by multiplying the area of the house and height of the house.

Volume = Area\times height

Volume = A\times h

Area and height of the house are known, so we substitute these value in above equation.

Volume = 2050\times 10

Volume = 20500\ ft^{3}

Now we convert the unit from feet to meter.

Divide the volume by 3.2808 for m^{3}

Volume = \frac{20500}{3.2808}

Volume = 6248.48\ m^{3}

Therefore, the volume of the house is 6248.48 m^{3}

8 0
4 years ago
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