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1 year ago

What is the mass amount of a Proton and a Neutron?

Physics

1 answer:

zysi [14]1 year ago

6 0

The masses amount of a proton and neutron are 1.0087 and 1.0073 amu respectively.

<h3>What is a Proton?</h3>

This is defined as sub atomic particle which is positively charged and is present in the nucleus while the neutron is also a particle present in the nucleus but has a neutral charge.

Electrons on the other hand are found outside the nucleus and are negatively charged. It is the sub atomic particle which is actively involved in a chemical reaction.

The masses of neutron and proton are 1.0087 and 1.0073 amu respectively and was discovered by scientists thereby making it the most appropriate choice.

Read more about Proton and Neutron here brainly.com/question/237857

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If the speed of a particle is doubled, what happens to its kinetic energy?

Norma-Jean [14]

Answer:

it increases

Explanation:

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2 years ago

An engine draws energy from a hot reservoir with a temperature of 1250 K and exhausts energy into a cold reservoir with a temper

dimulka [17.4K]

Answer:

The power output of this engine is $P = 17.5 W$

The the maximum (Carnot) efficiency is $\eta_c = 0.7424$

The actual efficiency of this engine is $\eta _a = 0.46$

Explanation:

From the question we are told that

The temperature of the hot reservoir is $T_h = 1250 \ K$

The temperature of the cold reservoir is $T_c = 322 \ K$

The energy absorbed from the hot reservoir is $E_h = 1.37 *10^{5} \ J$

The energy exhausts into cold reservoir is $E_c = 7.4 *10^{4} J$

The power output is mathematically represented as

$P = \frac{W}{t}$

Where t is the time taken which we will assume to be 1 hour = 3600 s

W is the workdone which is mathematically represented as

$W = E_h -E_c$

substituting values

$W = 63000 J$

$P = \frac{63000}{3600}$

$P = 17.5 W$

The Carnot efficiency is mathematically represented as

$\eta_c = 1 - \frac{T_c}{T_h}$

$\eta_c = 1 - \frac{322}{1250}$

$\eta_c = 0.7424$

The actual efficiency is mathematically represented as

$\eta _a = \frac{W}{E_h}$

substituting values

$\eta _a = \frac{63000}{1.37*10^{5}}$

$\eta _a = 0.46$

7 0

3 years ago

A 100-m-long wire carrying a current of 4.0 A will be accompanied by a magnetic field of what strength at a distance of 0.050 m

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Answer:

1.6 x 10^-5 T

Explanation:

i = 4 A

r = 0.05 m

The magnetic field due to long wire at a distance r is given by

$B = \frac{\mu _{0}}{4\pi }\times \frac{2i}{r}$

B = 10^-7 x 2 x 4 / 0.05

B = 1.6 x 10^-5 T

3 0

3 years ago

Will give brainliest! 50 points!!!

tatiyna

Answer:

Im not totally sure but that's what my science teacher taught me sorry if is wrong

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3 years ago

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