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drek231 [11]
4 years ago
6

Which of the following describes an element? Choose all that apply.

Chemistry
1 answer:
Korvikt [17]4 years ago
8 0

Answer:

A, D,F

Explanation:

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morpeh [17]
It is letter C: Continental crust is thicker than oceanic crust.
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3 years ago
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BY ANSWERING THIS QUESTION UR PUTTING IT ON UR MOM's LIFE THAT U WON'T STEAL MY POINTS.
Yakvenalex [24]

Answer:

T_2=-125.58\°C

Explanation:

Hello!

In this case, considering the Gay-Lussac's law which describes the pressure-temperature behavior as a directly proportional relationship by holding the volume as constant, we write:

\frac{T_1}{P_1} =\frac{T_2}{P_2}

Whereas solving for the final temperature T2, we get:

T_2=\frac{T_1P_2}{P_1}

Thus, we plug in the given data (temperature in Kelvins) to obtain:

T_2=\frac{(22+273.15)K*1.75atm}{3.50atm} \\\\T_2=147.58K-273.15\\\\T_2=-125.58\°C

Best regards!

3 0
3 years ago
How do many types of cells, like bacteria, reproduce?
umka2103 [35]

Answer:

cells like bacteria are bisexual so they split and their offspring is 100 percent like the parent and this process happens over and over

Explanation:

8 0
2 years ago
if 45.0 ml of 1.50 M Ca(OH)2 are needed to neutralize 25.0 ml of HI of unknown concentration, what is the molarity of the HI?
ipn [44]

Answer:

M of HI = 5.4 M.

Explanation:

  • We have the rule: at neutralization, the no. of millimoles of acid is equal to the no. of millimoles of the base.

<em>(XMV) acid = (XMV) base.</em>

where, X is the no. of (H) or (OH) reproducible in acid or base, respectively.

M is the molarity of the acid or base.

V is the volume of the acid or base.

<em>(XMV) HI = (XMV) Ca(OH)₂.</em>

For HI; X = 1, M = ??? M, V = 25.0 mL.

For Ca(OH)₂, X = 2, M = 1.5 M, V = 45.0 mL.

<em>∴ M of HI = (XMV) Ca(OH)₂ / (XV) HI</em> = (2)(1.5 M)(45.0 mL) / (1)(25.0 mL) = <em>5.4 M.</em>

6 0
4 years ago
Which type of wave interaction is shown in the photo? with ISSN AN O A. Diffraction O B. Reflection O C. Refraction O D. Absorpt
il63 [147K]

Answer:

I believe the answer is B.) Reflection

I hope I helped! ^-^

6 0
3 years ago
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