B)The concentration of the acid (C₁) is the same as that of the base (C₂).
V₁=V₂
n(acid)=C₁V₁
n(base)=C₂V₂
HX + YOH = YX + H₂O
n(acid)=n(base)
C₁V₁=C₂V₂
C₁=C₂
Answer; both inside the cell body and inside the axon.
Answer:
108.81 K
Explanation:
First convert 17 °C to Kelvin:
Assuming ideal behaviour, we can solve this problem by using the<em> combined gas law</em>, which states that at constant composition:
Where in this case:
We <u>input the data</u>:
- 800 torr * 100 L * T₂ = 600 torr * 50 L * 290.16 K
And <u>solve for T₂</u>:
First you have a knowledge of bond order which is
B.O=(no. of electrons in bonding orbital - no. of electrons in non-bonding orbital)÷2
Note:
bond strength is directly proportional to bond order.
For oxygen:
B.O=(6-2)/2= 2; after the removal of two electrons(removal occur from non-bonding orbital)
B.O=(6-0)/2= 3 (As B.O increased bond strength increased)
For Nitrogen:
B.O=(6-0)/2= 3; after the removal of two electrons(removal occur from bonding orbital)
B.O=(4-0)/2= 2 (As B.O decreased bond strength decreased)
