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lara31 [8.8K]
3 years ago
12

What is the term for a substance that acts on proton donor in one reaction and as a proton acceptor in another?

Chemistry
1 answer:
kolezko [41]3 years ago
3 0
<span>Proton donor  is a Bronsted-Lowry acid , 
and </span> proton acceptor  of protons is a Bronsted-Lowry base.
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I need help!!! Please
irinina [24]

Answer:

B

Explanation:

7 0
3 years ago
What mass of oxalic acid dihydrate, H2C2O4•2H2O, is needed to make a 0.357 M solution of oxalic acid in a 250.0mL volumetric fla
GalinKa [24]

Molarity is expressed as the number of moles of solute per volume of the solution. The mass of oxalic acid dihydrate needed for the solution is calculated as follows:

Amount in moles: (0.357 mol H2C2O4•2H2O / L) (.250 L ) = 0.0893 mol H2C2O4•2H2O


Amount in mass : 0.0893 mol H2C2O4•2H2O (126.08 g / mol ) = 11.2589 g H2C2O4•2H2O


Hope this answers the question. Have a nice day.

5 0
3 years ago
How many grams are in 0.02 moles of beryllium iodide, Bel2?
Flura [38]
This set up of a conversion table should show you that if you multiply the grams of BeI2 times .02 moles, it equals <span>5.256 g (your answer) </span>

8 0
3 years ago
A mixture of three noble gases has a total pressure of 1.25 atm. The individual pressures exerted by neon and argon are 0.68
FinnZ [79.3K]

First of all, as you seen the gases are noble which means that will not react with each other and in this case each gas create individual pressure.  

P_{T}= total pressure  

P_{Ne} = pressure of neon  

P_{Ar} = pressure of argon  

P_{He} = pressure of helium {which is required}

P_{T} = P_{Ne} + P_{Ar} + P_{He}    

1.25 = 0.68 + 0.35 +  P_{He}

P_{He}   = 1.25  - [0.68 + 0.35] = 0.22 atm

4 0
3 years ago
In a sulphuric acid (h2so4) - sodium hydroxide (naoh) acid-base titration, 17.3 ml of 0.126 m naoh is needed to neutralize 25 ml
katen-ka-za [31]
The balanced equation for the neutralisation reaction is as follows
2NaOH + H₂SO₄ ---> Na₂SO₄ + 2H₂O
stoichiometry of NaOH to H₂SO₄ is 2:1
the number of moles of NaOH reacted  - 0.126 mol/L  x 0.0173 L = 0.00218 mol
if 2 mol of NaOH reacts with 1 mol of H₂SO₄ 
then 0.00218 mol of NaOH reacts with - 0.00218 / 2 = 0.00109 mol of H₂SO₄ 
molarity is the number of moles of solute in 1 L solution
therefore if 25 mL contains - 0.00109 mol 
then 1000 mL contains - 0.00109 mol / 25 mL  x 1000 mL = 0.0436 mol/L
therefore molarity of H₂SO₄ is 0.0436 M
4 0
3 years ago
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