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vredina [299]
3 years ago
13

The electrons stripped from glucose in cellular respiration end up in which compound? The electrons stripped from glucose in cel

lular respiration end up in which compound?
b. Carbon Dioxide
d. oxygen
Chemistry
1 answer:
Airida [17]3 years ago
6 0
The final destination to where some of the electrons go to at the end of cellular respiration would be D. Oxygen. Assuming that this aerobic cellular respiration, the final electron acceptor is that of oxygen.
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A solution is prepared at that is initially in benzoic acid , a weak acid with , and in sodium benzoate . Calculate the pH of th
Kisachek [45]

Answer:

pH=4.1

Explanation:

Hello,

In this case, for a concentration of 0.42 M of benzoic acid whose Ka is 6.3x10⁻⁵ in 0.33 M sodium benzoate, we use the Henderson-Hasselbach equation to compute the required pH:

pH=pKa+log(\frac{[base]}{[acid]} )

Whereas the concentration of the base is 0.33 M and the concentration of the acid is 0.42 M, thereby, we obtain:

pH=-log(Ka)+log(\frac{[base]}{[acid]} )\\\\pH=-log(6.3x10^{-5})+log(\frac{0.33M}{0.42M} )\\\\pH=4.1

Regards.

3 0
4 years ago
How many days pass until the exact same Moon shape reappears?
Troyanec [42]
22 because that how many days it will take for the exact moon shape to pass and it will then reappear.
4 0
4 years ago
I’m extremely stuck on this, please help
nataly862011 [7]

Answer:

ice: 2,100 J/(kg·K)

water: 4,200 J/(kg·K)

water vapor: 2,000 J/(kg·K)

basalt: 840 J/(kg·K)

granite: 790 J/(kg·K)

aluminum: 890 J/(kg·K)

iron: 450 J/(kg·K)

copper: 380 J/(kg·K)

lead: 130 J/(kg·K)

Explanation:

Specific heat is the amount of thermal energy you need to supply to a sample weighing 1 kg to increase its temperature by 1 K.

5 0
3 years ago
if 26.8g of copper (ll) chloride are dissolved in sufficient water to make 4.00 L of solution, what is the molarity of the solut
artcher [175]

Answer: Molarity of the solution is 4.97 \times 10^{-2} M and water is the solvent.

Explanation:

Given: Mass of solute = 26.8 g

Volume = 4.00 L

Now, moles of copper (II) chloride (molar mass = 134.45 g/mol) are calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{26.8 g}{134.45 g/mol}\\= 0.199 mol

Molarity is the number of moles of a substance divided by volume of solution in liter.

Therefore, molarity of given solution is calculated as follows.

Molarity = \frac{no. of moles}{Volume (in L)}\\= \frac{0.199 mol}{4.00 L}\\= 0.04975 M\\= 4.97 \times 10^{-2} M

Solvent is defined as a component which is present in higher amount in a solution. Generally, a solvent is present in liquid state but it can also be a solid or gas.

In the given solution, copper (II) chloride is dissolved in water so copper (II) chloride is the solute and water is the solvent.

Thus, we can conclude that molarity of the solution is 4.97 \times 10^{-2} M and water is the solvent.

4 0
4 years ago
Sandy puts a paper clip on the table. Then, she puts a magnet near the paperclip. The paperclip begins to move.
Akimi4 [234]
Applied forces/or unbalanced:i hope that helps you
3 0
4 years ago
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