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Sonbull [250]
3 years ago
6

A) What mass in grams of H20 is needed to react completely with 40.0 g of

Chemistry
1 answer:
Step2247 [10]3 years ago
7 0

Answer:

m_{H_2O}=9.24gH_2O

Explanation:

Hello there!

In this case, since there is a 2:2 mole ratio between sodium peroxide and water according to the given reaction, it is possible to apply the following stoichiometric setup for the calculation of the required mass of water:

m_{H_2O}=40.0gNa_O_2*\frac{1molNa_O_2}{78gNa_O_2}*\frac{2molH_2O}{2molNa_O_2}  *\frac{18.02gH_2O}{1molH_2O} \\\\m_{H_2O}=9.24gH_2O

Best regards!

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I          2.62 x 10⁻⁴               0                2.62 x 10⁻⁴

C          -x                            +x              +x

E       2.62 x 10⁻⁴ - x           +x              2.62 x 10⁻⁴ + x

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[OH⁻] = 3.8 x 10⁻¹¹

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