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Lerok [7]
3 years ago
11

explain one or two things that adversely (negatively) affect the Earth's environment. How do you know that these things you're d

iscussing are bad for the world around us?
Chemistry
2 answers:
zimovet [89]3 years ago
8 0

Answer:

Humans impact the physical environment in many ways: overpopulation, pollution, burning fossil fuels, and deforestation. Changes like these have triggered climate change, soil erosion, poor air quality, and undrinkable water.

BartSMP [9]3 years ago
3 0

Answer:

Hello! The main thing I will be talking about today is two things that negatively affect the Earth's environment. Humans have impacted the physical environment is many ways, two being, overpopulation. Overpopulation is becoming a problem in this world. Accidental births are the main reason. Overpopulation can cause economic problems, over-farming, deforestation, and even water polluting. Second thing is, burning toxic fumes, and creating pollution. Pollution is a very, very bad thing. It can cause the atmosphere to fill up with fumes which aren't good for plants, humans, or animals. Pollution can take the form of chemical substances or energy, such as noise, heat, or light. There are four main types of air pollution sources: mobile sources,  such as cars, buses, planes, trucks, and trains. stationary sources, such as power plants, oil refineries, industrial facilities, and factories. area sources, such as agricultural areas, cities, and wood burning fireplaces. I know the things I'm discussing are bad because, slowly the Earth is taking impact because of us. We need to make a better change and help our Earth.

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. The heat capacity of a bomb calorimeter was determined by burning 6.79 g methane (energy of combustion 802 kJ/mol CH4) in the
kolbaska11 [484]

Answer:

a) The heat capacity of the calorimeter is 31.4 kJ/ºC.

b) The energy of combustion of acetylene in kJ/mol is 1097 kJ/mol.

Explanation:

The heat capacity ( C ) of a substance is <em>the amount of heat required to raise the temperature  of a given quantity of the substance by one degree Celsius</em>. Its units are J/°C. or kJ/ºC.  

If we know the heat capacity and the amount of a substance, then the change in  the sample’s temperature (Δt ) will tell us the amount of heat (<em>q</em>) that has been absorbed  or released in a particular process. One of the equations for calculating the heat change is  given by:

q=C.ΔT

Where ΔT is the temperature change: ΔT= tfinal - tinitial, and C the heat capacity.

In the calorimeter, the heat given off by the sample is absorbed by the water and the bomb. The special design of the calorimeter enables us to assume that no heat (or mass) is lost to the surroundings during the time it takes to make measurements.

Therefore, we can call the bomb and the water in which it is submerged an isolated system. Because no heat enters or leaves the system throughout the process,  the heat change of the system ( q system ) must be zero and we can write:

qsystem = qrxn + qcal

qsystem = 0

where q cal and q rxn are the heat changes for the calorimeter and the reaction, respectively.  Thus, qrxn = -qcal

To calculate <em>q</em>cal , we need to know the heat capacity of the calorimeter ( Ccal ) and the  temperature rise, that is, <em>qcal = Ccal. ΔT</em>

a. The quantity Ccal is calibrated by burning a substance with an accurately known heat  of combustion. In order to do this, we need to convert the molar heat of combustion (expressed in kJ/mol) into heat of combustion (expressed in kJ). For that matter, we transform the 6.79 grams of methane into moles:

1 mol CH₄÷16.04 g CH₄ × 6.79 g CH₄ = 0.423 mol CH₄

And then multiply it by the molar heat of combustion:

802 kJ/mol × 0.423 mol = 339 kJ

Now we know that that the combustion of 6.79 g of methane releases 339 kJ of heat. If the temperature rise is 10.8ºC, then the heat capacity of the calorimeter is given by

Ccal= qcal/ΔT = 339 kJ/10.8ºC = 31.4 kJ/ºC

Once C cal has been determined, the calorimeter can be used to measure the heat of  combustion of other substances.  Note that although the combustion reaction is exothermic, q cal is a positive quantity because it represents the heat absorbed by the calorimeter.

b. The heat absorbed by the bomb and water is equal to the product of the heat  capacity and the temperature change. Working with the same equation, and assuming no heat is lost to  the surroundings, we write

qcal=Ccal.ΔT= 31.4 kJ/°C × 16.9 °C = 531kJ

Now that we have the heat of combustion, we need to calculate the molar heat.   Because qsystem = qrxn + qcal and qrxn = -qcal, the heat change of the reaction is -531 kJ.

This is the heat released by the combustion of 12.6 g of acetylene ; therefore, we can write  the conversion factor as 531 kJ÷12.6 g

The molar mass of acetylene is 26.04 g, so the heat of combustion of 1 mole of acetylene is

 molar heat of combustion= -531 kJ÷12.6 g × 26.04 g÷ 1 mol= 1097 kJ/mol

Therefore, the energy of combustion of acetylene in kJ/mol is 1097 kJ/mol.

7 0
4 years ago
A tree is an example
zzz [600]
The answer is A it’s tall
8 0
3 years ago
How does the development of the heliocentric model show how scientists ideas change over time?
12345 [234]

Answer: Italian scientist Giordano Bruno was burned at the stake for teaching, among other heretical ideas, Copernicus' heliocentric view of the Universe. In 1543, Nicolaus Copernicus detailed his radical theory of the Universe in which the Earth, along with the other planets, rotated around the Sun.

4 0
3 years ago
A book with a weight of 12 N rests on its back cover. If the back cover measures 0.21 m by 0.28 m, how much pressure does the bo
erik [133]

Answer:

option D = 204 Pa

Explanation:

Given data:

Weight of book = 12 N

Area of book =  0.21 m × 0.28 m = 0.0058 m²

Pressure of book = ?

Solution:

formula

pressure = force / area

P = f/ A

now we will put the values in formula,

P = 12 N/ 0.0058  m²

P= 204 Nm⁻²      ( Nm⁻²= Pa)

P = 204 Pa

4 0
3 years ago
What is the atomic mass of an element is equal to?
Tatiana [17]
Protons and Neutrons is what determines the atomic mass. I cannot further explain this answer, however, I hope I helped!
6 0
3 years ago
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