1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
cricket20 [7]
3 years ago
13

A bicycle manufacturer is studying the reliability of one of its models. The study finds that the probability of a brake defect

is 4 percent and the probability of both a brake defect and a chain defect is 1 percent.
If the probability of a defect with the brakes or the chain is 6 percent, what is the probability of a chain defect?
Mathematics
2 answers:
Murrr4er [49]3 years ago
7 0
The answer is 3 percent... hope tht helps :)
dangina [55]3 years ago
4 0

Answer:

The probability of a chain defect is 3%.

Step-by-step explanation:

Given : A bicycle manufacturer is studying the reliability of one of its models. The study finds that the probability of a brake defect is 4 percent and the probability of both a brake defect and a chain defect is 1 percent.

If the probability of a defect with the brakes or the chain is 6 percent

To find : What is the probability of a chain defect?

Solution :

Let A be the event of brake defect

and B be the event of chain defect.

We have given, P(A)= 4%=0.04

P(A and B) = 1%=0.01

P(A or B)= 6%=0.06

We have to find P(B),

The formula used is,

P(A \text{ or } B) = P(A) + P(B) - P(A \text{ and } B)

Substitute the value,

0.06= 0.04+ P(B) - 0.01

0.06= 0.03+ P(B)

0.06-0.03=P(B)

P(B)=0.03

or P(B)=3\%

Therefore, The probability of a chain defect is 3%.

You might be interested in
Help me please i only have a small amount of time
Sveta_85 [38]

Answer: 0.83

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
Evaluate the expression. Choose the best answer. <br><br><br><br><br><br> <img src="https://tex.z-dn.net/?f=8%5EP4" id="TexFormu
Morgarella [4.7K]
N P r = (n!)/((n-r)!)
8 P 4 = (8!)/((8-4)!)
8 P 4 = (8!)/(4!)
8 P 4 = (8*7*6*5*4!)/(4!)
8 P 4 = 8*7*6*5
8 P 4 = 1680

The final answer is 1680

4 0
4 years ago
Question 3
gladu [14]
The answer is a) 16.
5 0
3 years ago
Explain why 256 + 4 is equivalent to (200 + 4) + (40+4) + (164)​
laiz [17]

The expression 256 + 4 is equivalent to (200 + 4) + (40+4) + (16+4) according to distributive and commutative property of addition.

Given the expression 256 + 4. This can be solved using the partial sum expressed as:

256 + 4

256 + 4

= (200 + 40 + 16) + 4

According to the commutative property, A+B = B+A

The arrangement does not affect the result. Hence;

  • (200 + 40 + 16) + 4 = 4 +  (200 + 40 + 16)

Using the distributive law;

  • 4 +(200 + 40 + 16) = (200 + 4) + (40 + 4) + (16 + 4)

Hence the expression 256 + 4 is equivalent to (200 + 4) + (40+4) + (16+4) according to distributive and commutative property of addition.

​Learn more on  partial sum  here: brainly.com/question/6958503

4 0
3 years ago
B=ym+y for m   m=   help me solve thank u
Sveta_85 [38]
B = ym + y

B - y = ym

(B - y) / y = m
or
B/y - 1 = m


7 0
4 years ago
Other questions:
  • Miss Hoffman gave 90-cent tip to a waitress for serving a meal costing $6.00 what percent of the bill is her tip?
    13·1 answer
  • Which relations are functions? Select Function or Not a function for each graph.
    6·2 answers
  • A student scored 81 and 93 on her first two quizzes. Write and solve a compound inequality to
    7·1 answer
  • Please answer 63 points for the answer
    12·1 answer
  • If I have a mass of 40g and a volume of 20ml, then what is the density?
    11·2 answers
  • The cost of a sapling of Mango, Jamun and Peepal is Rs 25, Rs 15 and Rs 10 each. The labour
    11·1 answer
  • 5. Sam wrote the expression below.
    8·1 answer
  • What is the y-intercept of the line?
    14·1 answer
  • Anyone happen to know the answer?
    10·1 answer
  • What is the remainder when 48,240 is divided by 412?
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!