Acceleration = (Vf - Vi)/t
Since Vf= 60m/s
Vi= 15m/s
T= 15s
=> a= (60m/s - 15m/s)/15s
= 3
So the acceleration is 3m/s^2
Based on the attached image:
- The name of the longitude line that passes through point A is the International Date Line
- The longitude 180° is experiencing solar noon because the rays of the sun are parallel to it.
- The longitude for 6 pm is 90° W, 12 midnight is 0°, and 6 am is 90° E
- Longitude 120° is B
- Solar time at Point B is 4 pm
- The location will correspond to any point on the same latitude as A
<h3>What are lines of longitude?</h3>
Lines of longitude are imaginary lines which run along the earth from the North pole. to the South pole.
Longitude lines divide the earth into semi-circles.
Longitude lines are known as meridians and each meridian measures one arc degree of longitude.
Considering the attached image:
- The name of the longitude line that passes through point A is the International Date Line
- The longitude 180° is experiencing solar noon because the rays of the sun are parallel to it.
- The longitude for 6 pm is 90° W, 12 midnight is 0°, and 6 am is 90° E
- Longitude 120° is B
- Solar time at Point B is 4 pm
- the location will correspond to any point on the same latitude as A
In conclusion, longitude lines are imaginary lines and run from North to South on the earth.
Learn more about lines of longitude at: brainly.com/question/1939015
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Answer:
Frequency required will be 2421.127 kHz
Explanation:
We have given inductance 
Current in the inductor 
Voltage v = 13 volt
Inductive reactance of the circuit 

We know that


f = 2421.127 kHz
Question:
A particle moving along the x-axis has a position given by x=(24t - 2.0t³)m, where t is measured in s. What is the magnitude of the acceleration of the particle at the instant when its velocity is zero
Answer:
24 m/s
Explanation:
Given:
x=(24t - 2.0t³)m
First find velocity function v(t):
v(t) = ẋ(t) = 24 - 2*3t²
v(t) = ẋ(t) = 24 - 6t²
Find the acceleration function a(t):
a(t) = Ẍ(t) = V(t) = -6*2t
a(t) = Ẍ(t) = V(t) = -12t
At acceleration = 0, take time as T in velocity function.
0 =v(T) = 24 - 6T²
Solve for T
Substitute -2 for t in acceleration function:
a(t) = a(T) = a(-2) = -12(-2) = 24 m/s
Acceleration = 24m/s