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Zolol [24]
3 years ago
8

A spearfisher stands in shallow water and sees a fish a few feet in front of her. She throws her spear directly toward the posit

ion she perceives the fish to be in. Where does the spear end up relative to the fish, assuming the fish does not move?
Physics
1 answer:
DENIUS [597]3 years ago
5 0

Answer:

the spear will end up above the fish relative to the actual position of the fish.

Explanation:

due to refraction of light coming from the fish the fish will appear slightly above from its real position

So due to this refraction the spearfisher will throw the spear directly at the image of the fish due to which it will not reach the position of fish but it will reach the position above the fish.

So here we can say that the spear will end up above the fish relative to the actual position of the fish

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tape measure?

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3 years ago
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Every second, the Sun converts about 600 million tons of hydrogen into 596 million tons of helium. The remaining 4 million tons
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Answer:

Converted to an amount of energy equal to 4 million tons times the speed of light squared. ejected into space in a solar wind.

Explanation:

The 4 million tons of mass is converted to the amount of energy that is equal to 4 million tons times the speed of light squared. This energy moves from the sun with the help of solar winds and received by the planets present in the solar system. This solar energy moves in the form of solar radiation because there is no medium for propagation so that's why we can say that the mass is converted into energy that moves in the form of radiation in discrete packets.

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2 years ago
A positively charged objectwith a mass of 0.114 kg oscillates at the end of a spring, generating ELF (extremely low frequency) r
katen-ka-za [31]

Answer:

  • k = 167.33 N/m

Explanation:

  • The radio waves have a fixed relationship between the propagation speed (the speed of light in vacuum), the frequency and the wavelength, as follows:
  • v = c = λ*f

        where c= speed of light in vacuum = 3*10⁸ m/s, λ = wavelength =  

        4.92*10⁷ m.

        Solving for f, we get the frequency of the radio waves:

        f = 6.1 Hz

  • Now, from the Hooke's law, we know that the mass attached at the end of the spring oscillates with an angular frequency defined by  a fixed relationship between the spring constant k and the mass m, as follows:

       \omega_{o}^{2} =\frac{k}{m}  (1)

  • Now, we know that there exists a fixed relationship between the angular frequency and the frequency, as follows:

       \omega = 2*\pi *f (2)    

  • We also know that f in (2) is the same that we got for the radio waves, so replacing (2) in (1), and rearranging terms, we can solve for k, as follows:
  • k = 4*\pi ^{2}*f^{2} *m = 4*\pi ^{2} * (6.1Hz)^{2} * 0.114 kg = 167.33 N/m

3 0
2 years ago
A 2430 pound roller coaster starts from rest and is launched such that it crests a 105 ft high hill with a speed of 59 mph. The
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Answer:

Explanation:

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mass of roller coaster m=\frac{W}{g}=\frac{2430}{32.2}=75.45

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drag force f_d=85\ pounds

velocity at top v=59 mph\approx 86.53\ ft/s

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Conserving Energy at bottom and top

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E=0.5\times 75.45\times 86.53^2+2430\times 105+85\times 396

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A. Speed of light (Apex) 
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