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Zolol [24]
4 years ago
8

A spearfisher stands in shallow water and sees a fish a few feet in front of her. She throws her spear directly toward the posit

ion she perceives the fish to be in. Where does the spear end up relative to the fish, assuming the fish does not move?
Physics
1 answer:
DENIUS [597]4 years ago
5 0

Answer:

the spear will end up above the fish relative to the actual position of the fish.

Explanation:

due to refraction of light coming from the fish the fish will appear slightly above from its real position

So due to this refraction the spearfisher will throw the spear directly at the image of the fish due to which it will not reach the position of fish but it will reach the position above the fish.

So here we can say that the spear will end up above the fish relative to the actual position of the fish

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The gauge pressure at a particular depth of ocean water is calculated as:

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Here \rho is the density of water, P is the required pressure, h is the depth of water, and g is the gravitational acceleration.

Step-2:

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$$\\\begin{aligned}\\P&=\rho gh\\&=1030 (\text{ kg/m}^3)\times 9.8 (\text{ m/s}^2)\times 2452 \text{ m}\\&=24.75\times 10^6 \text{ Pa}\times\frac{1 \text{ atm}}{10.1325 \times10^4 \text{ Pa}}\\&=224.268 \text{ atm}\\\end{aligned}\\$$

Learn more about gauge pressure here,

brainly.com/question/14012416

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