Question

A chemist must dilute of aqueous sodium carbonate solution until the concentration falls to . He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in milliliters. Be sure your answer has the correct number of significant digits.

Answer 1

The question is incomplete, complete question is :

A chemist must dilute 73.9 mL of 400 mM aqueous sodium carbonate  solution until the concentration falls to 125 mM . He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Be sure your answer has the correct number of significant digits.

Answer:

The final volume of the solution will be 0.236 L.

Explanation:

Concentration of sodium carbonate solution before dilution =$M_1= 400 mM$

Volume of sodium carbonate solution before dilution = $V_1=73.9 mL$

Concentration of sodium carbonate solution after dilution =$M_2= 125 mM$

Volume of sodium carbonate solution after dilution = $V_2=?$

Dilution equation is given by:

$M_1V_1=M_2V_2$

$V_2=\frac{M_1V_1}{M_2}$

$V_2=\frac{400 mM\times 73.9 mL}{125 mM}= 236.48 mL\approx 236 mL$

1 mL = 0.001 L

236 mL = 0.236 L

The final volume of the solution will be 0.236 L.