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Serggg [28]
3 years ago
15

What is the pH of a solution with a [H+] of 1.0 x 10-4 M?

Chemistry
1 answer:
MaRussiya [10]3 years ago
4 0
PH = -log [H+]
pH = -log (1.0x10^-4) = -(-4) = 4 or A
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Plz answer for brainliest trolls will get deleted
Roman55 [17]

Answer:

A; C6H12O6 + 6O2

Explanation:

You can easily differentiate between the reactants and the products, as the reactants are on the left, while the products are on the right.

3 0
3 years ago
Convert 7.50 grams of glucose C6H12O6 to moles
Lera25 [3.4K]

Answer:

The number of mole is 0.04167mole

Explanation:

To convert gram to mole, we need to calculate the molecular weight of the compound

C6H12O6

C - 12

H - 1

O - 16

Molecular weight = 6 * 12 + 1 *12 + 6 * 16

= 72 + 12 + 96

= 180g/mol

To covert gram to mole

Therefore,

= 7.50g/ 180g/mol

= 0.04167 mole of glucose

3 0
3 years ago
The equilibrium constant for the reaction AgBr(s) Picture Ag+(aq) + Br− (aq) is the solubility product constant, Ksp = 7.7 × 10−
barxatty [35]

Answer:

The reaction will be  non spontaneous at these concentrations.

Explanation:

AgBr(s)\rightarrow Ag^+(aq) + Br^- (aq)

Expression for an equilibrium constant K_c:

K_c=\frac{[Ag^+][Br^-]}{[AgCl]}=\frac{[Ag^+][Br^-]}{1}=[Ag^+][Br^-]

Solubility product of the reaction:

K_{sp}=[Ag^+][Br^-]=K_c=7.7\times 10^{-13}

Reaction between Gibb's free energy and equilibrium constant if given as:

\Delta G^o=-2.303\times R\times T\times \log K_c

\Delta G^o=-2.303\times R\times T\times \log K_{sp}

\Delta G^o=-2.303\times 8.314 J/K mol\times 298 K\times \log[7.7\times 10^{-13}]

\Delta G^o=69,117.84 J/mol=69.117 kJ/mol

Gibb's free energy when concentration [Ag^+] = 1.0\times 10^{-2} M and [Br^-] = 1.0\times 10^{-3} M

Reaction quotient of an equilibrium = Q

Q=[Ag^+][Br^-]=1.0\times 10^{-2} M\times 1.0\times 10^{-3} M=1.0\times 10^{-5}

\Delta G=\Delta G^o+(2.303\times R\times T\times \log Q)

\Delta G=69.117 kJ/mol+(2.303\times 8.314 Joule/mol K\times 298 K\times \log[1.0\times 10^{-5}])

\Delta G=40.588 kJ/mol

  • For reaction to spontaneous reaction:  \Delta G.
  • For reaction to non spontaneous reaction:  \Delta G>0.

Since ,the value of Gibbs free energy is greater than zero which means reaction will be non spontaneous at these concentrations

5 0
3 years ago
As the movement of molecules within a substance increases, describe the change in heat of the substance. Justify your response i
Vladimir [108]
It will get hotter, because the molecules create heat when they move around just like us when we run.
3 0
3 years ago
Read 2 more answers
Use LeChâtelier's principle explain why the concentration of NO at equilibrium increases when the reacuon takes place at higher
Tatiana [17]

increasing the temperature shifts the equilibrium in the direction of the reaction in which heat is absorbed.

Explanation:

The concentration of NO at equilibrium will increase when the reaction takes place at a higher temperature because increasing the temperature shifts the equilibrium in the direction of the reaction in which heat is absorbed.

The reaction is an endothermic reaction.

                            N₂  + O₂  + heat  ⇄  2NO

According to Le Chatelier's principle, "if any of the conditions of a system in equilibrium is changed the system will adjust itself in order to annul the effect of the change".

  • In an endothermic reaction, heat is usually absorbed.
  • We see that in the backward reaction, heat is absorbed.
  • If the temperature of this reaction is increased, the backward reaction is favored more.
  • Since the reactants are combining better, more products NO results.

learn more:

Thermodynamics of reactions brainly.com/question/10567109

#learnwithBrainly

6 0
3 years ago
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