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scoundrel [369]
3 years ago
5

What is the equation that passes through the points (5,2) and has a slope of 3

Mathematics
1 answer:
charle [14.2K]3 years ago
4 0

Answer:

y=3x-13

Step-by-step explanation:

First, write your equation: y=3x+b. Plug in your ordered pair to the equation, it should look like this: 2=3(5)+b. 3 times 5 equals 15. This is what your equation should look like: 2=15+b. Subtract 15 from both sides to get -13 as your y-intercept. Go back to your original equation and plug in -13 to b. This is your final equation: y=3x-13. Hope this helped!

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Simplify 5 - (-1) please help me
devlian [24]

Answer:

Step-by-step explanation:

5 - (-1) = 5 + 1 = 6

3 0
3 years ago
Si la probabilidad de que un recién nacido sea niño es de 1 de dos opciones, representado en fracción 1/2, ¿Cuál es la probabili
Leno4ka [110]

Answer:

1/2 o 50%

Step-by-step explanation:

debemos partir de la presuncion que un bebe puede ser niño o niña uinicamente, o sea la P(niño) + P(niña) = 1

no existen los bebes que son niños y niñas al mismo tiempo, eso quiere decir que es una opcion o la otra

P(niña) = 1 - P(niño) = 1 - 1/2 = 1/2 = 0.5 = 50%

8 0
2 years ago
I need HELP!! With <br> 31, 33, 35 please explain
rusak2 [61]
For 31 you need 6% OF 50 meaning you need to multiply. 50*0.06=3. The answer for 31 is 3.

To find 33 you need to divide 1 by 0.4 to find how much you need to multiply 28 by. 1/0.4= 2.5 then you need to do 2.5*28 which would equal 70. The answer for 33 is 70.

To find 35 you need to notice that it DECREASES in meaning the bigger number (20) would be the denominator of the fraction and 15 would be the numerator. Therefore the fraction would b 15/20 or 75% of 20 would equal out to 15.
3 0
3 years ago
Read 2 more answers
Write a polynomial f (x) that satisfies the given conditions. Polynomial of lowest degree with zeros of -4 (multiplicity 3), 1 (
yuradex [85]

Answer:

Step-by-step explanation:

Polynomial f(x) has the following conditions: zeros of -4 (multiplicity 3), 1 (multiplicity 1), and with f(0) = 320.

The first part zeros of -4 means (x+4) and multiplicity 3 means (x+4)^3.

The second part zeros of 1 means (x-1) and multiplicity 1 means (x-1).

The third part f(0) = 320 means substituting x=0 into (x+4)^3*(x-1)*k =320

(0+4)^3*(0-1)*k = 320

-64k = 320

k = -5

Combining all three conditions, f(x)

= -5(x+4)^3*(x-1)

= -5(x^3 + 3*4*x^2 + 3*4*4*x + 4^3)(x-1)

= -5(x^4 + 12x^3 + 48x^2 + 64x - x^3 - 12x^2 - 48x - 64)

= -5(x^4 + 11x^3 + 36x^2 + 16x -64)

= -5x^3 -55x^3 - 180x^2 - 80x + 320

8 0
3 years ago
Read 2 more answers
Help me ?!?! Pleaseee
Mars2501 [29]

Answer:

C.

Step-by-step explanation:

Hope this helps! :)

6 0
3 years ago
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