Question

For the equation bacl2 na2so4 → baso4 2nacl, how many chlorine atoms are in the reactants side and the products side

Answer 1

The balanced chemical reaction is written as follows:

bacl2 + na2so4 → baso4 + 2nacl

Therefore, the number of chlorine atoms in the reactants side and the products side would be 2 atoms in both sides which should be the case because the number of atoms in each side should have the same number.

Answer 2

Answer: There are 2 chlorine atoms on reactant side and two chlorine atoms on product side.

Explanation: $BaCl_2+Na_2SO_4\rightarrow BaSO_4+2NaCl$

The given balanced equation follows the law of conservation of mass, which states the mass on product side must be equal to the mass on reactant side.

This can happen only if the number of atoms are same on both sidesof the arrow. There are 2 chlorine atoms in $BaCl_2$ and 2 chlorine atoms in $2NaCl$