This should be able to help you
Answer:
SN1 = a stepwise loss of a leaving group to form a carbocation followed by nucleophilic attack
Explanation:
Since 2-methyl-2-butanol is tertiary alcohol, the first step will be loss of leaving group to form a 3° carbocation which is very stable and favours SN1, followed by attack of nucleophile
Answer:
b. radicals form easily in the presence of chlorine radicals.
Explanation:
Chlorine radicals perform the first propagation step: because "radicals form easily in the presence of chlorine radicals."
This is because the first propagation step consumes a CHLORINE RADICAL while the second propagation step regenerates a CHLORINE RADICAL. In this way, a chain reaction occurs, whereby one CHLORINE RADICAL can ultimately cause thousands of molecules of methane to be converted into chloromethane with C12 present.
Hence, in this case, the correct answer is that "radicals form easily in the presence of chlorine radicals."
Answer:
Isotopes are atoms that have different number of neutrons, so they have a different mass number than the other atoms in an element.
If the pressure on an ideal gas is increased, the volume of the gas will decrease. This can be predicted with the use of the ideal gas equation which is expressed as: PV = nRT. At constant temperature, we can say that pressure and volume are inversely related. Thus, as one value increase, the other decrease.
