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Mandarinka [93]
3 years ago
6

How long would this acceleration last

Physics
1 answer:
Aleksandr-060686 [28]3 years ago
6 0
It would last as long as the applied force continued, or until the accelerating object hit something.
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lana [24]

Your best bet is to go with D.

6 0
3 years ago
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what are two properties that lead to electromagnetic interactions? pls help I'm so confused and cant find the answer anywhere!!
MArishka [77]

Answer:

Electric charge. A fundamental property that leads to the electromagnetic interactions among particles that make up matter.

8 0
3 years ago
A satellite is orbiting the earth just above its surface. The centripetal force making the satellite follow a circular trajector
Pavlova-9 [17]

Answer:

v=7905m/s

t=5063s

Explanation:

A satellite is orbiting the earth just above its surface. The centripetal force making the satellite follow a circular trajectory is just its weight, so its centripetal acceleration is about 9.81 m/s2 (the acceleration due to gravity near the earth's surface). If the earth's radius is about 6370 km, how fast must the satellite be moving? How long will it take for the satellite to complete one trip around the earth?

The weight of the satellite is the centripetal force, so:

W=mg=F_{cp}=ma_{cp}=m\frac{v^2}{r}

Which means: g=\frac{v^2}{r}

We can calculate then the velocity:

v=\sqrt{gr}=\sqrt{(9.81m/s^2)(6370000m)}=7905m/s

For calculating how long will it take for the satellite to complete one trip around Earth we consider that the distance of the trip is the circumference of the orbit. This is calculated as C=2\pi r.

Since velocity is v=d/t, we have:

t=d/v=C/v=2\pi r/v=\frac{2\pi 6370000}{7905m/s} =5063s

5 0
3 years ago
What is the moment of inertia of an object that rolls without slipping down a 3.5-m- high incline starting from rest, and has a
Daniel [21]

Answer:

I = 0.287 MR²

Explanation:

given,

height of the object = 3.5 m

initial velocity = 0 m/s

final velocity  = 7.3 m/s

moment of inertia = ?

Using total conservation of mechanical energy

change in potential energy will be equal to change in KE (rotational) and KE(transnational)

PE = KE(transnational) + KE (rotational)

mgh = \dfrac{1}{2}mv^2 + \dfrac{1}{2}I\omega^2

v = r ω

mgh = \dfrac{1}{2}mv^2 + \dfrac{1}{2}\dfrac{Iv^2}{r^2}

I = \dfrac{m(2gh - v^2)r^2}{v^2}

I = \dfrac{mr^2(2\times 9.8 \times 3.5 - 7.3^2)}{7.3^2}

I =mr^2(0.287)

I = 0.287 MR²

3 0
3 years ago
A cake is removed from a 350◦F oven and placed on a cooling rack in a 70◦F room. After 30 minutes the cake is 200◦F. When will i
galben [10]

Answer:

350 F to 100 F it take approx 87.33 min  

Explanation:

given data

oven = 350◦F

cooling rack = 70◦F

time = 30 min

cake = 200◦F

solution

we apply here Newtons law of cooling  

\frac{dT}{dt} = -k(T-Ta)

\frac{dy}{dt} = \frac{d}{dt} (T(t) -Ta)

= \frac{dT}{dt} -\frac{dTa}{dt} =\frac{dT}{dt} = -k(T-Ta)

-ky \frac{dy}{dt} = -ky

T(t) -Ta = (To -Ta) e^{-kt} T(t) = Ta+ (To -Ta)  e^{-kt}

put her value for time 30 min and T(t) = 200◦F and To =350◦F  and Ta = 70◦F

so here

200 = 70 + ( 350 - 70 ) e^{-k30}

k = 0.025575

so here for  T(t) = 100F

100 = 70 + ( 350 - 70 ) e^{-0.025575*t}

time = 87.33 min

so here 350 F to 100 F it take approx 87.33 min  

5 0
4 years ago
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