PLEASE HELP!! WILL MARK BRAINLIEST!!
2 answers:
Answer:
C.
Step-by-step explanation:
To see if x-3 is a factor you plug in what makes it 0 which is 3.
Evaluating f at 3:
14
So the remainder of dividing f by (x-3) is actually 14.
The conclusion is still the same but the work Devon provided with her conclusion is wrong as she suppose to evaluate f(3) instead of f(-3).
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Answer:
a) 40 feet
b) 54 ft/min
c) 4 mins
Step-by-step explanation:
Solution:-
- Kesha models the height ( h ) of the baton from the ground level but thrown from a platform of height hi.
- The function h ( t ) is modeled to follow a quadratic - parabolic path mathematically expressed as:
h ( t ) = −16t² + 54t + 40
Which gives the height of the baton from ground at time t mins.
- The initial point is of the height of the platform which is at a height of ( hi ) from the ground level.
- So the initial condition is expressed by time = 0 mins, the height of the baton h ( t ) would be:
h ( 0 ) = hi = -16*(0)^2 + 54*0 + 40
h ( 0 ) = hi = 0 + 0 + 40 = 40 feet
Answer: The height of the platform hi is 40 feet.
- The speed ( v ) during the parabolic path of the baton also varies with time t.
- The function of speed ( v ) with respect to time ( t ) can be determined by taking the derivative of displacement of baton from ground with respect to time t mins.
v ( t ) = dh / dt
v ( t )= d ( −16t² + 54t + 40 ) / dt
v ( t )= -2*(16)*t + 54
v ( t )= -32t + 54
- The velocity with which Kesha threw the baton is represented by tim t = 0 mins.
Hence,
v ( 0 ) = vi = -32*( 0 ) + 54
v ( 0 ) = vi = 54 ft / min
Answer: Kesha threw te baton with an initial speed of vo = 54 ft/min
- The baton reaches is maximum height h_max and comes down when all the kinetic energy is converted to potential energy. The baton starts to come down and cross the platform height hi = 40 feet and hits the ground.
- The height of the ball at ground is zero. Hence,
h ( t ) = 0
0 = −16t² + 54t + 40
0 = -8t^2 + 27t + 20
- Use the quadratic formula to solve the quadratic equation:
Answer: The time taken for the baton to hit the ground is t = 4 mins
Answer: approximately 49 feets
Step-by-step explanation:
The diagram of the tree is shown in the attached photo. The tree fell with its tip forming an angle of 36 degrees with the ground. It forms a right angle triangle,ABC. Angle C is gotten by subtracting the sum of angle A and angle B from 180(sum of angles in a triangle is 180 degrees).
To determine the height of the tree, we will apply trigonometric ratio
Tan # = opposite/ adjacent
Where # = 36 degrees
Opposite = x feets
Adjacent = 25 feets
Tan 36 = x/25
x = 25tan36
x = 25 × 0.7265
x = 18.1625
Height of the tree from the ground to the point where it broke = x = 18.1625 meters.
The entire height of the tree would be the the length of the fallen side of the tree, y + 18.1625m
To get y, we will use Pythagoras theorem
y^2 = 25^2 + 18.1625^2
y^2 = 625 + 329.88
y^2 = 954.88
y = √954.88 = 30.9 meters
Height of the tree before falling was
18.1625+30.9 = 49.0625
The height of the tree was approximately 49 feets
