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Serggg [28]
3 years ago
7

PLEASE HELP!! WILL MARK BRAINLIEST!!

Mathematics
2 answers:
katen-ka-za [31]3 years ago
7 0

Answer:

C. Yes Devon should have evaluated f(3).

Step-by-step explanation:

She substituted the wrong value. For x - 3 to be a factor f(3) must equal 0.

f(3) = 3^3 + 3^2 - 10(3) + 8 = 27 + 9 - 30 + 8

= 14,  so x- 3 is not a factor anyway but she did  substitute the wrong value.

ser-zykov [4K]3 years ago
6 0

Answer:

C.

Step-by-step explanation:

To see if x-3 is a factor you plug in what makes it 0 which is 3.

Evaluating f at 3:

3^3+3^2-10(3)+8

27+9-30+8

36-30+8

6+8

14

So the remainder of dividing f by (x-3) is actually 14.

The conclusion is still the same but the work Devon provided with her conclusion is wrong as she suppose to evaluate f(3) instead of f(-3).

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Suppose that 75% of all trucks undergoing a brake inspection at a certain inspection facility pass the inspection. Consider grou
RSB [31]

Answer:

b) 0.2961

c) 0.2251

d) Mean = 11.25, Standard deviation =  1.667  

Step-by-step explanation:

We are given the following information:

We treat trucks undergoing a brake inspection passin as a success.

P( trucks undergoing a brake inspection passes the test) = 75% = 0.75

a) Conditions for binomial probability distribution

  1. There are n independent trial.
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  3. The probability of success is same for all trials.

Then the number of trucks undergoing a brake inspection follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 15

b) P(proportion of groups will between 8 and 10 trucks pass the inspection)

We have to evaluate:

P(8\leq x \leq 10) = P(x = 8) + P(x = 9) + P(x = 10)\\= \binom{15}{8}(0.75)^8(1-0.75)^7 + \binom{15}{9}(0.75)^9(1-0.75)^6 + \binom{15}{10}(0.75)^{10}(1-0.75)^5\\= 0.0393 + 0.0917 + 0.1651\\= 0.2961

c) P( exactly 3 trucks fail the inspection)

p = 0.25

P(x = 3)\\= \binom{15}{3}(0.25)^3(1-0.25)^{12}\\=0.2251

d) Mean and standard deviation

\mu = np = 15(0.75) = 11.25\\\sigma = \sqrt{np(1-p)} = \sqrt{15(0.75)(1-0.75)} = 1.667

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Answer:

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Step-by-step explanation:

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