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Serggg [28]
3 years ago
7

PLEASE HELP!! WILL MARK BRAINLIEST!!

Mathematics
2 answers:
katen-ka-za [31]3 years ago
7 0

Answer:

C. Yes Devon should have evaluated f(3).

Step-by-step explanation:

She substituted the wrong value. For x - 3 to be a factor f(3) must equal 0.

f(3) = 3^3 + 3^2 - 10(3) + 8 = 27 + 9 - 30 + 8

= 14,  so x- 3 is not a factor anyway but she did  substitute the wrong value.

ser-zykov [4K]3 years ago
6 0

Answer:

C.

Step-by-step explanation:

To see if x-3 is a factor you plug in what makes it 0 which is 3.

Evaluating f at 3:

3^3+3^2-10(3)+8

27+9-30+8

36-30+8

6+8

14

So the remainder of dividing f by (x-3) is actually 14.

The conclusion is still the same but the work Devon provided with her conclusion is wrong as she suppose to evaluate f(3) instead of f(-3).

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Simply divide with your calculator

18049/14 ≈ 1289.214

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3 years ago
PLEASE HELP ME OUT...
e-lub [12.9K]

Answer:

y=-3

Step-by-step explanation:

there is no slope so x will not be used in the equation it also crosses at -3

3 0
3 years ago
What is the average rate of change for the function f(x)=3x^2 -5 on the interval −3 ≤ x ≤ −1 ?
Anestetic [448]

Answer:

-12

Step-by-step explanation:

Let b = -1 and a = -3

The average rate of change = \frac{f(b) - f(a)}{b - a}

f(b) = f(-1) = 3(-1)^2 - 5 = 3 - 5 = -2

f(a) = f(-3) = 3(-3)^2 - 5 =27 - 5 = 22

f(b) - f(a) = -2 - 22 = -24

b - a = -1 + 3 = 2

\frac{f(b) - f(a)}{b - a} = -24/2 = -12

4 0
3 years ago
How do I figure out the sequence? (Fractions) *I GIVE THANKS
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4 0
3 years ago
Read 2 more answers
The heights of young women aged 20 to 29 follow approximately the N(64, 2.7) distribution. Young men the same age have heights d
murzikaleks [220]

Answer: 10.703%

Step-by-step explanation:

Let minimum height of the tallest 25% of young women be M.

Let Q be the random variable which denotes the height of young women.

Therefore, Q – N(64,2.70)

Now, P(Q˂M) = 1-0.25

i.e. P[(Q-64)/2.7 ˂ (M-64)/2.7] = 0.75

I.e. ф-1 [(M-64)/2.7] = 0.75 i.e. (M-64)/2.7 = ф-1 (0.75) = 0.675 i.e. M = 65.8198 inches

Let R be the random variable denoting the height of young men

Therefore, R – N (69.3, 2.8)

i.e. (R-69.3)/2.8 – N(0,1)

therefore the probability required = P(R ˂65.8198) = P[(R-69.3)/2.8 ˂ (65.8198 – 69.3)/2.8]

this gives P[(R-69.3)/2.8 ˂] = ф (-1.2429) = 0.107033

From this, the percentage of young men shorter than the shortest amongst the tallest 25% of young women is 10.703%

4 0
3 years ago
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