Question

How would I do this question.

Answer 1

Answer:

The density of cube is 6.17959 $\frac{g}{cm^{3} }$

Step-by-step explanation:

The density is given by ration of a mass of body and volume occupied by a body.

$\rho = \frac{m}{V}$

Where,

$\rho$ is density.

m is mass of a body

V is the volume of a body

Given that one side of the cube is 0.53cm

Hence, the volume of a body is V=$0.53^{3}$=0.148877$cm^{3}$

Now, the Density of the cube will be

$\rho = \frac{m}{V}$

$\rho = \frac{0.92}{0.148877}$

$\rho =6.17959$

Thus, The density of cube is 6.17959 $\frac{g}{cm^{3} }$