Answer:
length = 35ft, width = 20ft
Step-by-step explanation:
We are working with length (L), width (W), and area (A). We are asked to find the 2 dimensions. The question tells us that L = W + 15, so we can express L in terms of W. However, we still don't know what A is. Since we have 2 unknowns, we somehow need to develop 2 equations to get a solvable system.
We can set up the first equation using the relationship between L and W:

We can set up the second equation using the information in the second sentence:

Now we can plug the first equation, already isolated for A, into the second equation and solve for W:

A pretty nasty-looking equation actually becomes pretty easy to solve. We know the length is 15ft greater than the width, so if W=20, L=35.
\left[x _{4}\right] = \left[ \frac{ - \left( -1\right) ^{\frac{3}{4}}\,\sqrt[4]{\left( 20 - 21\,z^{2}\right) }}{\sqrt[4]{4}}\right][x4]=[4√4−(−1)434√(20−21z2)]
I hope helping with u
<h2>The value of StartFraction 6 Over x EndFraction + 2x2, when x = 3 is 20.</h2>
Explanation:
The given expression is 
When x = 3, the expression becomes 

= 2 + 18 = 20
Answer:
x^2 + y^2 = 12
Step-by-step explanation:
For a circle with the center at the origin [(h,k) is (0,0)]
use the formula:
x^2 + y^2 = r^2
In this case r is 2sqroot3.
(2sqroot3)^2 is 12.
2•2•sqrt3•sqrt3
= 4•3
= 12
So we get,
x^2 + y^2 = 12
Answer:
96% percent and fraction is 24/25