Question

. Current of 1.5A is

Answer 1

Answer:

B = 4 T

Explanation:

We have,

Length of a wire is 1 m

The wire is placed at an angle of 30 degrees with uniform magnetic field. It is required to find the strength of magnetic field. The force acting on a wire in magnetic field is given by:

$F=ILB\sin\theta$

$B=\dfrac{F}{IL\sin\theta}\\\\B=\dfrac{3}{1\times 1.5\times \sin(30)}\\\\B=4\ T$

So, the strength of magnetic field is 4 T.