Thank you for posting your question here at brainly. I think your question is incomplete. Below is the complete question, it can be found elsewhere:
What is the probability of finding an electron within one Bohr radius of the nucleus?<span>Consider an electron within the 1s orbital of a hydrogen atom. The normalized probability of finding the electron within a sphere of a radius R centered at the nucleus is given by 1-a0^2[a0^2-e^(-2R/a0)(a0^2+2a0R+2R2)]. Where a0 is the Bohr radius (for a hydrogen atom, a0 = 0.529 Å.). What is the probability of finding an electron within one Bohr radius of the nucleus? What is the probability of finding an electron of the hydrogen atom within a 2.30a0 radius of the hydrogen nucleus?
Below is the answer:
</span><span>you plug the values for A0 and R into your formula</span>
A change in the position of a body with respect to time relative to a reference point is motion.
Because there is no absolute point of reference, there is no true discernible absolute motion, and therefore, everything is said to be moving constantly.
Hope that helped =)
Acceleration is the change of velocity, and velocity is the change of distance. The opposite of finding change, or differentiation, is integration.
Acceleration = 1.3 m/s²
Velocity: ∫ 1.3 dx = 1.3x + c m/s
Distance: ∫ 1.3x dx = 1.3x²/2 + c m
Distance run: 1.3*3²/2 = 5.85 m
<em>What</em><em> </em><em>bad</em><em> </em><em>thing</em><em> </em><em>happened</em><em>?</em>
Answer: Meteor showers occur when the earth in its orbit around the Sun passes through debris left over from the destruction of comets.
Explanation:A meteor is a particle broken off an asteroid or comet orbiting the Sun, it burns up as it enters the Earth's atmosphere, creating the effect called shooting star. Cosmic debris of meteor is known as meteoroids. These meteoroids, entering Earth's atmosphere, at extremely high speeds on parallel trajectories is an event known as meteor shower.
Answer:
0.03924 m
Explanation:
Let g = 9.81 m/s2. Let x be the maximum distance that the spring will stretch. And let the potential energy reference point be at the the lower end where the spring is stretched to the maximum. Using mechanical energy conservation we have the following:
- At the bottom end where the spring is stretched to maximum: potential and kinetic energy is 0. Elastic energy is
- At the point where the weight is placed: potential energy is mgx, kinetic energy and elastic energy is 0 (because the spring is not stretched)