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Blababa [14]
3 years ago
9

How can I do this, can you explain me

Mathematics
1 answer:
Sergio039 [100]3 years ago
3 0

Answer:

Step-by-step explanation:

Start with h(t) = -16t^2 + initial height, which here is h(t) = -16t^2 + 1296.  Set this = to zero, which corresponds to the object hitting the ground (h = 0):

0 = -16t^2 + 1296.  Dividing all terms by -16, we get t^2 = 81, whose positive square root is 9.  It takes 9 seconds for the object to hit the ground.

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.ffffffffffffffffffffffffffffffffffffffffffffffff

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Distribute.<br><br> 1/2 (8x - 16)
Kitty [74]

Answer:

b. 4x-8

Step-by-step explanation:

1/2 x(8x-16)

= 1/2(8x) - 1/2 (16)

=4x - 8

Hope this helped

6 0
3 years ago
Read 2 more answers
Find the surface area of the composite figure.
ELEN [110]

Answer:

644cm^2

Step-by-step explanation:

First we'll work out the surface area of the pink figure.

That's the area of the two 5 by 6 rectangles on the top and bottom, plus the area of the two 5 by 20 and two 6 by 20 rectangles on the sides.

However, we note that the purple figure is blocking out a 6 by 12 section on the pink figure, so we'll need to subtract this.

The above works out to 2\times(30+100+120)-72=428 cm^2.

Then we'll work out the surface area of the purple figure.

This will be the area of the two 4 by 6 rectangles at the top and bottom, plus the area of the two 4 by 12 and one 6 by 12 rectangles on the sides. Note that there's only one 6 by 12 rectangle because the other face is joined to the pink figure, so it's blocked out.

That's 2\times(24+48)+72=216cm^2.

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6 0
2 years ago
The sum of four consecutive
Firdavs [7]

Answer:

42 is the smallest of the 4 numbers.

Step-by-step explanation:

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4 0
3 years ago
Add. (3b + 5) + (2b + 4)
zaharov [31]

Answer:

\huge{ \fbox{ \sf{5b + 9}}}

Step-by-step explanation:

\star{ \text{( \: 3b + 5) + (2b + 4)}}

\text{Step \: 1 \:  :  \sf{Remove \: the \: unnecessary \: parentheses}}

\text{When \: there \: is \: a \: ( + ) \: in \: front \: of \: an \: expression \: in \: parentheses \:, there \: is \: no \: need \: to \: change \: the \: sign \: of \: each \: term \: in \: the \: expression.}

\text{That \: means, \: the \: expression \: remains \: the \: same. \: Just \: you \: have \: to \: remove \: the \: parentheses.}

\mapsto{ \sf{3b + 5 + 2b + 4}}

\text{Step \: 2 \:  : Collect \: like \: terms.}

\text{Like \: terms \: are \: those \: which \: have \: the \: same \: base.}

\mapsto{ \sf{3b + 2b + 5 + 4}}

\mapsto{ \sf{5b + 5 + 4}}

\text{ Step \: 3 \:  :  \sf{Add \: the \: numbers : 5 \: and \: 4}}

\mapsto{ \boxed {\sf{ {5b + 9}}}}

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

4 0
3 years ago
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