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3 years ago

If the separation between two charges increases, how does the force

Chemistry

1 answer:

Leona [35]3 years ago

5 0

The force reduces

Explanation:

According to Coulomb's law, the force between the charges will reduce if the separation between the charges increases.

Coulomb's law states that "the force between two charges is a directly proportional to the product of the magnitude of the charges and inversely proportional to the square of their separation.".

F = $\frac{K q_{1} q_{2} }{r^{2} }$

where F is the electric field force

K is the constant of the field

$q_{1}$ is charge 1

$q_{2}$ is charge 2

r is the separation

We see that the separation is inversely proportional to the force between the charges. The larger the separation, the weaker or smaller the force.

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Newton's laws brainly.com/question/11411375

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Convert 0.00763 nL to L

Reptile [31]

Answer:

$7.63\cdot10^{-12} L$

Explanation:

Conversion problems could be solved using dimensional analysis for convenient use and understanding. Dimensional analysis is a technique of multiplying the measure we have by a fraction corresponding to some two equal measures in different units.

In order to apply dimensional analysis here, we firstly need to know that a prefix 'n' stands for 'nano', and nano means $10^{-9}$ . In this case, we have nanoliters. Using the prefix, we can find a relationship between nanoliter and liter:

$1 nL = 10^{-9} nL$

We may now apply dimensional analysis. Since we wish to convert into liters, we'll be multiplying the number we have in nL by a fraction that contains this relationship with liters in the numerator and nanoliters in the denominator, so that nL terms cancel out and we would obtain the final answer in liters:

$0.00763 nL\cdot \frac{10^{-9} L}{1 nL}=7.63\cdot10^{-12} L$

6 0

3 years ago

Drag the tiles to the correct boxes. Not all tiles will be used. The oxidation number of oxygen is -2, and that of chlorine is -

Evgen [1.6K]

Answer:

That oxidation number of chlorine is -1 while that of oxygen is -2

Explanation:

When it comes to manganese chloride to stabilize the chlorine Ion. Two manganese ions shall be required. Hence the formula for the compound becomes $M_nCl_2$ while the formula for manganese (iv) chloride will be $M_nCl_4$ similarly.

When oxygen and magnesium oxide is considered the Two ions of Manganese will satisfy to ions of oxygen. Which cancels and becomes $M_nO$ while for manganese (iv) oxide the formula becomes $M_nO_2$ .

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3 years ago

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The law of conservation of mass states that in a chemical reaction, mass is neither created nor destroyed. that means, the total

g100num [7]

Well all reactions need energy to start it. The light is the energy that the reaction requires to start it. Sunlight also has no mass in the first place so laws of conservation of mass don't apply to it.

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4 years ago

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Van der waals interactions result when hybrid orbitals overlap. a hydrogen atom loses an electron. molecules held by ionic bonds

vovangra [49]

Van der waals interactions are the electrical interactions between two or more atoms and even molecules but the inter-molecular attractions between the molecules are not exactly strong, in fact they are the weakest. And these Van der waals interactions are happened when electrons are not symmetrical distributed in a molecule.

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4 years ago

At 570 mm hg and 25 c a gas sample has a volume of 2270 ml what is the final pressure at a volume of 1250 ml?

ValentinkaMS [17]

Main Answer:

Given data:

Initial Pressure P1 = 570 mm hg

Initial Volume V1 = 2270 ml

Final Pressure P2 = ? mm hg

Final Volume V1 = 1250 ml

According to the ideal gas equation,

PV = constant.

P1V1 = P2V2

P2 = P1V1/V2

P2 = (570 x 2270) / 1250

P2 = 1035.12 mm hg

The final pressure at volume of 1250 ml is 1035.12 mm hg.

Explanation:

What is ideal gas equation ?

The ideal gas equation is as follows:

PV = nRT

where P = Pressure

V = Volume

n = number of moles of gas

R = Universal gas constant

T = Temperature

This ideal gas equation provides the macroscopic particles behavior of the gas. At this condition, the particles of the gas, won't be attract or repel each other. It is consider as the stable condition.

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3 0

2 years ago