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liq [111]
3 years ago
8

Which of the following statements about radiation is true?

Physics
1 answer:
omeli [17]3 years ago
7 0
I'm not sure but I think it is A.
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Describe briefly how you would check that the rule is horizontal in this experiment. You  may draw a diagram.​
aliina [53]

Answer:

We want to describe how to graph a linear equation.

Explanation:

The given equation is:

y = -4x - 1

a) To graph it, we need to find two points that belong to the line, then we graph the points, and then we connect them with a line.

To get the points, we just need to evaluate the function in two different values of x.

for x = 0

y = -4*0 - 1 = -1

So we have the point (0, -1)

for x = 1

y = -4*1 - 1 = -5

So we have the point (1, - 5)

Now we just need to find these two points and connect them with a line, the graph can be seen below.

b) To check if the graph is correct we can see two things:

in y = -4*x - 1

The y-intercept is -1, this means that the graph should intersect the y-axis at  y = -1

The slope is -4, this means that for each unit increase on x, we should see that the y-value decreases by 4.

Checking those two things we can see if our graph is correct or not.

pls give brainliest!

3 0
3 years ago
A backpack weighs 8.2 newtons and has a mass of 5kg on the moon. What is the strength of the gravity on the moon?
Pavel [41]
Weight is equivalent to the product of the mass of an object and the strength of the gravitational field.

Using:
F = ma

a = 8.2 / 5
a = 1.64 N/kg

The gravitational field strength is equivalent to 1.64 N/kg.
7 0
3 years ago
Suppose a radio signal (light) travels from Earth and through space at a speed of 3 × 10^8/ (this is the speed of light in vacuu
zlopas [31]

Answer:

Explanation:

we know that

s=vt here v is the speed and s is distance covered by the signals

given data

v=3*10^8

t=10 min we have to convert it into seconds

1 minute=60 seconds

so

10 minutes =10*60/1 =600 seconds

now putting the value of v and t we can find the value of s

s=vt

s=3*10^8*600

s=1.8*10^11m

i hope this will help you

8 0
3 years ago
What tension would you need to make a middle c (261.6 hz) fundamental mode on a 1 m string (for example, on a harp)? the linear
Allisa [31]
The frequency of middle C on a string is
f = 261.6 Hz.

The given linear density is
ρ = 0.02 g/cm = (0.02 x 10⁻³ kg)/(10⁻² m)
   = 0.002 kg/m

The length of the string is L = 1 m.

Let T =  the tension in the string (N).
The velocity of the standing wave is
v= \sqrt{ \frac{T}{\rho} }

In the fundamental mode, the wavelength, λ, is equal to the length, L.
That is
Because v = fλ, therefore
\sqrt{ \frac{T}{\rho} } =f \lambda = fL \\\\ \frac{T}{\rho} = (fL)^{2} \\\\ T = \rho (fL)^{2}

From given information, obtain
T = (0.002 kg/m)*(261.6 1/s)²*(1 m)²
   = 136.87 N

Answer: 136.9 N (nearest tenth)

4 0
3 years ago
Two particles of equal mass m are at the vertices of the base of an equilateral triangle. The triangle’s center of mass is midwa
Helga [31]

Answer:Twice of given mass

Explanation:

Given

Two Particles of Equal mass placed at the base of an equilateral Triangle

let mass of two equal masses be m and third mass be m'

Taking one of the masses at origin

Therefore co-ordinates of first mass be (0,0)

Co-ordinates of other equal mass is (a,0)

if a is the length of triangle

co-ordinates of final mass (\frac{a}{2},\frac{\sqrt{3}a}{2})

Given its center of mass is at midway between base and third vertex therefore

x_{cm},y_{cm}=\frac{a}{2},\frac{\sqrt{3}a}{4}

y_{cm}=\frac{m_1y_1+m_2y_2+m_3y_3}{m_1+m_2+m_3}

\frac{\sqrt{3}a}{4}=\frac{m\cdot 0+m\cdot 0+m'\cdot \frac{\sqrt{3}a}{2}}{m+m+m'}

2m+m'=4\times (\frac{m'}{2})

2m+m'=2m'

m'=2m

8 0
3 years ago
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