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Dafna11 [192]
3 years ago
12

According to Newton´s second law of motion, what does an object with more mass require? Question 8 options:

Physics
2 answers:
Novay_Z [31]3 years ago
6 0
More force to accelerate. If you push a car compared to a beach ball, which will you have to push harder for it to move? That's pretty much what the question is asking, if that helps any:) 
trapecia [35]3 years ago
6 0

more for force to accelerate

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<span>B. It stays the same</span>
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Defination wheel and axle​
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3 years ago
Two spectators at a soccer game see, and a moment later hear, the ball being kicked on the playing field. The time delay for the
WINSTONCH [101]

Answer:

a)188.65m

b)154.35m

c)243.7m

Explanation:

Given data:

t_A=0.55s

t_B=0.45s

(a) The distance from the kicker to each of the 2 spectators is given by:

d_A=v \times t_A

where,

v= speed of sound

t_A=time taken for the sound waves to reach the ears

d_A=343\times 0.55=188.65m

(b)d_B=v \times t_B

where,

v= speed of sound

t_B=time taken for the sound waves to reach the ears

d_B=343\times 0.45=154.35m

(c)As the angle b/w slight lines  from the two spectators to the player is right angle,

hypotenuse=the distance b/w 2 spectators

and, the slight lines are the other 2 lines

D^2=d_A^2+d_B^2\\D=\sqrt{188.65^2+154.35^2} \\D= 243.7m

5 0
3 years ago
To calculate the change in kinetic energy, you must know the force as a function of _______. The work done by the force causes t
aliya0001 [1]

To calculate the change in kinetic energy, you must know the force as a function of position. The work done by the force causes the kinetic energy change

Explanation:

The work-energy theorem states that the change in kinetic enegy of an object is equal to the work done on the object:

\Delta E_k = W

where the work done is the integral of the force over the position of the object:

W=\int F(x) dx

As we see from the formula, the magnitude of the force F(x) can be dependent from the position of the object, therefore in order to solve correctly the integral and find the work done on the object, it is required to know the behaviour of the force as a function of the position, x.

6 0
3 years ago
A parallel-plate capacitor in air has a plate separation of 1.76 cm and a plate area of
Monica [59]

Answer:

Explanation:

Plate separation, d = 1.76 cm = 0.0176 m

Area of plates, A = 25 cm^2 = 0.0025 m^2

V = 255 V

(a) Capacitance of capacitor

C = \frac{\epsilon _0A}{d}

C = \frac{8.854\times 10^{-12}\times 0.0025}{0.0176}

C = 1.258 x 10^-12 F

charge is same before and after immersion as the battery is disconnected

q = C V

q = 1.258 x 10^-12 x 255 = 3.2 x 10^-10 C

(b)

Capacitance before, C = 1.258 x 10^-12 C

capacitance after, C' = k x C = 80 x 1.258 x 10^-12 = 100.64 x 10^-12 C

Where, k is the dielectric constant of water = 80

Potential difference after immersion, V' = V / k = 255 / 80 = 3.1875 V

(c) initial energy,

U = \frac{q^{2}}{2C}

U = \frac{(3.2\times 10^{-10})^{2}}{2\times 1.258\times 10^{-12 }}=4.07\times 10^{-8}J

Final energy

U' = \frac{q^{2}}{2C'}

U' = \frac{(3.2\times 10^{-10})^{2}}{2\times 100.64\times 10^{-12}}=5.08\times 10^{-10}J

6 0
3 years ago
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