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topjm [15]
2 years ago
12

Suppose you put a whole antacid tablet in one glass of water and a crushed antacid tablet in another glass containing the same a

mount of water. Both tablets would start reacting and producing bubbles of gas. Use lesson concepts to predict which tablet would stop producing bubbles first. Explain your prediction. Then, with the permission of an adult, do the activity. Do your results agree with your prediction?
Chemistry
1 answer:
iogann1982 [59]2 years ago
3 0
The crushed tablets would stop bubbling/fuzzing first because it has a smaller surface area which means that it would dissolve before the uncrushed tablets which has a larger surface area.
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An aqueous KNO3 solution is made using 72.5 g of KNO3 diluted to a total solution volume of 2.00 L. Calculate the molarity, mola
Sonja [21]

Answer:

The molarity is 0.359\frac{moles}{L}

The molality is 0.354 \frac{moles}{kg}

The mass percent of the solution es 3.45%

Explanation:

Molarity is a unit of concentration that indicates the amount of moles of solute that appear dissolved in each liter of the mixture. It is determined by:

Molarity (M)=\frac{number of moles of solute}{volume}

Being:

  • K: 39 g/mole
  • N: 14 g/mole
  • O: 16 g/mole

The molar mass of KNO₃ is:

KNO₃=  39 g/mole + 14 g/mole + 3*16 g/mole= 101 g/mole

You can apply the following rule of three: if 101 grams of KNO₃ are present in 1 mole, 72.5 grams in how many moles are present?

moles of KNO_{3}=\frac{72.5 grams*1 mole}{101 grams}

moles of KNO₃= 0.718

So you have:

  • moles of KNO₃= 0.718
  • volume= 2 L

Applying this quantity in the definition of molarity:

molarity=\frac{0.718 moles}{2 L}

Molarity= 0.359\frac{moles}{L}

<u><em>The molarity is 0.359</em></u>\frac{moles}{L}<u><em></em></u>

Molality is a way of measuring the concentration of solute in solvent and indicates the amount of moles of solute in each kilogram of solvent.

Then the molality is calculated by:

Molality=\frac{moles of solute}{mass of solvent in kilograms}

Density is defined as the property that matter, whether solid, liquid or gas, has to compress in a given space. That is, it is the amount of mass per unit volume. So, if the density of 1.05 g / mL for the solution indicates that in 1 mL of solution there are 1.05 grams of solution, in 2000 mL (where 2L = 2000 mL, because 1 L = 1000mL) how much mass is there?

mass=\frac{2000 mL*1.05 grams}{1 mL}

mass= 2100 grams

Since mass solution = mass water + mass KNO₃

then mass water = mass solution - mass KNO₃

Being mass solution 2100 grams and mass KNO₃ 72.5 grams, and replacing you get: mass water= 2100 grams - 72.5 grams

mass water= 2,027.5 grams

Then, being:

  • moles of KNO₃= 0.718
  • mass of solvent in kilograms= 2.0275 kg (being 2,027.5 grams= 2.0275 kilograms because 1,000 grams= 1 kilogram)

Replacing in the definition of molality:

molality=\frac{0.718 moles}{2.0275 kg}

molality= 0.354 \frac{moles}{kg}

<u><em>The molality is 0.354 </em></u>\frac{moles}{kg}<u><em></em></u>

The mass percent of a solution is the number of grams of solute per 100 grams of solution. Then the mass percent is the mass of the element or solute divided by the mass of the compound or solute and the result of which is multiplied by 100 to give a percentage.

mass percent=\frac{mass of solute}{mass of solution} *100

So, in this case:

mass percent=\frac{72.5 grams}{2100 grams} *100

mass percent= 3.45 % KNO₃ by mass

<u><em>The mass percent of the solution es 3.45%</em></u>

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Ionic bonds are different from covalent bonds. identify the characteristics of ionic bonds
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One atom is a metal and one is a nonmetal. 
One atom has high electronegativity value, while the other value is really low 
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Answer:

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Two unknown molecular compounds were being studied. A solution containing 5.00 g of compound A in 100. g of water froze at a low
Shtirlitz [24]

Answer:

Compound B.

Explanation:

The freezing point depression is a colligative property. It depends on the number of particles (moles) present in the solution.

\Delta T_{\text{f}} = K_{\text{f}} b

where b is the molal concentration

b = \dfrac{\text{moles of solute}}{\text{kilograms of solvent}}\\\\n = \dfrac{\text{mass}}{\text{molar mass}} = \dfrac{m}{M}

If m is constant (5 g), then

n \propto \dfrac{1}{M}

The compound with the greater molar mass has fewer moles and therefore fewer particles to depress the freezing point.

That must be Compound B, because Compound A has the lower freezing point.

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What type of reaction is sodium reacting with chlorine
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Answer:

combination reaction

Explanation:

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