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bearhunter [10]
3 years ago
11

The block in this illustration is floating in water, which has a density of 1.00 g/cm3 .What is a good estimate of the density o

f the block if about 30 percent of the block is below water?
Chemistry
1 answer:
miss Akunina [59]3 years ago
6 0

Answer : The density of the block is estimated to be, 0.30g/cm^3.

Explanation :

Density of the water, \rho_w=1.0 g/cm^3

As we know that,

Buoyant force = \rho\times volume\times g

where,

g = gravitational acceleration

volume of the block = v

density of the block = \rho_o

Weight of the Block = Buoyant force exerted by water

\rho_o\times v\times g=\rho_w\times 30\%\text{ of volume of block}\times g

\rho_o\times v\times g=\rho_w\times 0.30v\times g

\rho_o\times v\times 9.8 m/s^2=1 g/cm^3\times 0.30v\times 9.8 m/s^2

\rho_o=0.30 g/cm^3

Thus, the density of the block is estimated to be, 0.30g/cm^3.

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