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san4es73 [151]
3 years ago
14

For each of the following compounds, state whether it is ionic or covalent, and if it is ionic, write the symbols for the ions i

nvolved: (a) KClO4 (b) Mg(C2H3O2 )2 (c) H2S (d) Ag2S (e) N2Cl4 (f) Co(NO3)2
Chemistry
1 answer:
kupik [55]3 years ago
6 0

Answer :

Covalent compound : It is defined as the compound which is formed by the sharing of electrons between the atoms forming a compound.

The covalent compound are usually formed when two non-metals react.

Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.

All the polyatomic ions always form an ionic compound.

Polyatomic ions : It is a charged species that composed of two or more atoms and these charged species are bonded by the covalent bond.

For the given options:

Option A:  KClO_4

This compound is formed by the combination of potassium, K^+ which is a metal and ClO_4^- ion which is a polyatomic ion. Thus, it will form an ionic compound.

Option B:  Mg(C_2H_3O_2)_2

This compound is formed by the combination of magnesium, Mg^{2+} which is a metal and C_2H_3O_2^{-} ion which is a polyatomic ion. Thus, it will form an ionic compound.

Option C:  H_2S

Hydrogen and sulfur, both are non-metals and they will form a covalent compound.

Option D:  Ag_2S

This compound is formed by the combination of silver, Ag^{+} which is a metal and sulfur, S^{2-} which is a non-metal. Thus, it will form an ionic compound.

Option E:  N_2Cl_4

Nitrogen and chlorine, both are non-metals and they will form a covalent compound.

Option F:  Co(NO_3)_2

This compound is formed by the combination of cobalt, Co^{2+} which is a metal and NO_3^{-} ion which is a polyatomic ion. Thus, it will form an ionic compound.

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Which pair of elements would you expect to exhibit the greatest similarity in their physical
galben [10]

Answer:

e. I, At

Explanation:

Hello!

In this case, since the periodic trends of a series of elements belonging to the same group towards physical and chemical properties tend to be the same when closer in period, we notice that Mg and Al, Br and Kr and As and Br are close but in period, not in the same group; therefore e. I, At, iodine and astatine, are going to tend to exhibit the greatest similarity in their physical  and chemical properties.

Best regards!

3 0
3 years ago
Ammonia (NH3(g), es001-1.jpgHf = –46.19 kJ/mol) reacts with hydrogen chloride (HCl(g), es001-2.jpgHf = –92.30 kJ/mol) to form am
SIZIF [17.4K]
Answer is: enthalpy for this reaction is -175.91 kJ.
Chemical reaction: NH₃ + HCl → NH₄Cl.
ΔrH = ∑ΔfH(products of reaction) - ∑ΔfH(reactants).
ΔrH = ΔfH(NH₄Cl) - (ΔfH(NH₃) + ΔfH(HCl)).
ΔrH = -314.4 kJ/mol · 1 mol - (-46.19 kJ/mol · 1 mol + (-92.30 kJ/mol) · 1 mol).
ΔrH = -314.4 kJ + 138.49 kJ.
ΔrH = -175.91 kJ.
5 0
4 years ago
Read 2 more answers
if the nuclide has a half-life of 8.0 days , what mass of the nuclide remains in the patient at 6:00 p.m. the next day? (assume
nata0808 [166]

The mass of the nuclide that will remain in the patient at 6:00 p.m. the next day is 94 g

<h3>How to determine the number of half-lives that has elapsed</h3>

We'll begin by obtaining the number of half lives that has elapsed. This can be obtained as follow:

  • Half-life (t½) = 8 days = 8 × 24 = 192 hours
  • Time (t) = 6 pm next day = 18 hours
  • Number of half-lives (n) =?

n = t / t½

n = 18 / 192

n = 0.09375

<h3>How to determine the amount remaining </h3>
  • Original amount (N₀) = 100 g
  • Number of half-lives (n) = 0.09375
  • Amount remaining (N) = ?

N = N₀ / 2^n

N = 100 / (2^0.09375)

N = 94 g

Thus, 94 g of the nuclide is remaining in the patient's body,

Learn more about half life:

brainly.com/question/26374513

#SPJ1

4 0
2 years ago
A solution (HELP ASSAAAAP ROAD TO GRADUATION)
creativ13 [48]

Hey there! A simple explanation is below.

Answer:

D) is a single phase homogeneous mixture.

Explanation:

A solution is a form of homogenous combination made up of two or more components in chemistry. A solute is a material that is dissolved in another material, known as a solvent, in such a combination. The mixing of a solution takes place at a scale where the effects of chemical polarity are present, resulting in solvation-specific interactions. In most cases, the solution is in the condition of the solvent, because it is most common in the mixture.

3 0
3 years ago
A student carried out a titration using HC2H3O2(aq)HC2H3O2(aq) and NaOH(aq)NaOH(aq). The net ionic equation for the neutralizati
AnnZ [28]

Answer:

The amount of HC₂H3₃2(aq) in the flask after the addition of 5.0mL of NaOH(aq) compared to the amount of HC₂H₃O₂(aq) in the flask after the addition of 1.0mL is much smaller because more HC₂H₃O₂(aq) is required to react with 5.0 mL NaOH than with 1.0 mL NaOH.

Explanation:

Equation of the reaction between acetic acid, HC₂H₃O₂(aq) and sodium hydroxide, NaOH(aq) is given below:

CH₃COOH (aq) + NaOH (aq) ----> CH₃COONa (aq) + H₂O

The equation of the reaction shows that acetic acid andsodium hydroxide will react in a 1:1 ratio

Since the concentration of NaOH was not given, we can assume that the concentration is 0.01 M

Moles of NaOH in 5.0 mL of 0.01 M NaOH = 0.01 × 5/1000 = 0.00005 moles

Moles of NaOH in 1.0 mL of 0.01 M NaOH = 0.01 ×1/1000 = 0.0001 moles

Ratio of moles of NaOH in 5.0 mL to 1.0 mL = 0.00005/0.00001 = 5

There are five times more moles of NaOH in 5.0 mL than in 1.0 mL and this means that 5 times more the quantity of HC₂H₃O2(aq) required to react with 1.0 mL NaoH is needed to react with 5.0 mL NaOH.

Therefore, the amount of HC₂H₃O2(aq) in the flask after the addition of 5.0mL of NaOH(aq) compared to the amount of HC₂H₃O₂(aq) in the flask after the addition of 1.0mL is much smaller because more HC₂H₃O₂(aq) is required to react with 5.0 mL NaOH than with 1.0 mL NaOH.

4 0
3 years ago
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