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san4es73 [151]
3 years ago
14

For each of the following compounds, state whether it is ionic or covalent, and if it is ionic, write the symbols for the ions i

nvolved: (a) KClO4 (b) Mg(C2H3O2 )2 (c) H2S (d) Ag2S (e) N2Cl4 (f) Co(NO3)2
Chemistry
1 answer:
kupik [55]3 years ago
6 0

Answer :

Covalent compound : It is defined as the compound which is formed by the sharing of electrons between the atoms forming a compound.

The covalent compound are usually formed when two non-metals react.

Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.

All the polyatomic ions always form an ionic compound.

Polyatomic ions : It is a charged species that composed of two or more atoms and these charged species are bonded by the covalent bond.

For the given options:

Option A:  KClO_4

This compound is formed by the combination of potassium, K^+ which is a metal and ClO_4^- ion which is a polyatomic ion. Thus, it will form an ionic compound.

Option B:  Mg(C_2H_3O_2)_2

This compound is formed by the combination of magnesium, Mg^{2+} which is a metal and C_2H_3O_2^{-} ion which is a polyatomic ion. Thus, it will form an ionic compound.

Option C:  H_2S

Hydrogen and sulfur, both are non-metals and they will form a covalent compound.

Option D:  Ag_2S

This compound is formed by the combination of silver, Ag^{+} which is a metal and sulfur, S^{2-} which is a non-metal. Thus, it will form an ionic compound.

Option E:  N_2Cl_4

Nitrogen and chlorine, both are non-metals and they will form a covalent compound.

Option F:  Co(NO_3)_2

This compound is formed by the combination of cobalt, Co^{2+} which is a metal and NO_3^{-} ion which is a polyatomic ion. Thus, it will form an ionic compound.

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The heat of vaporization of acetic acid is . Calculate the change in entropy when of acetic acid condenses at .
Umnica [9.8K]

The question is incomplete, the complete question is;

The heat of vaporization ΔHv of acetic acid HCH3CO2 is 41.0 /kJmol. Calculate the change in entropy ΔS when 954.g of acetic acid condenses at 118.1°C. Be sure your answer contains a unit symbol. Round your answer to 3 significant digits.

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-1.67 JK-1

Explanation:

Since Heat of vaporization of acetic acid = 41.0 kJ/mol

Therefore:

Heat of condensation of acetic acid = -41.0 kJ/mol

Mass of acetic acid = 954 g

Temperature of condensation = 118.1 °C or 391.1 K

Number of moles of acetic acid = 954 g/60g/mol = 15.9 moles

Heat evolved during condensation = 15.9 moles *  -41.0 kJ/mol = -651.9 KJ

Entropy change (ΔS) = Heat evolved/ Temperature = -651.9 KJ/391.1 K

Entropy change (ΔS) = -1.67 JK-1

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