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san4es73 [151]
3 years ago
14

For each of the following compounds, state whether it is ionic or covalent, and if it is ionic, write the symbols for the ions i

nvolved: (a) KClO4 (b) Mg(C2H3O2 )2 (c) H2S (d) Ag2S (e) N2Cl4 (f) Co(NO3)2
Chemistry
1 answer:
kupik [55]3 years ago
6 0

Answer :

Covalent compound : It is defined as the compound which is formed by the sharing of electrons between the atoms forming a compound.

The covalent compound are usually formed when two non-metals react.

Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.

All the polyatomic ions always form an ionic compound.

Polyatomic ions : It is a charged species that composed of two or more atoms and these charged species are bonded by the covalent bond.

For the given options:

Option A:  KClO_4

This compound is formed by the combination of potassium, K^+ which is a metal and ClO_4^- ion which is a polyatomic ion. Thus, it will form an ionic compound.

Option B:  Mg(C_2H_3O_2)_2

This compound is formed by the combination of magnesium, Mg^{2+} which is a metal and C_2H_3O_2^{-} ion which is a polyatomic ion. Thus, it will form an ionic compound.

Option C:  H_2S

Hydrogen and sulfur, both are non-metals and they will form a covalent compound.

Option D:  Ag_2S

This compound is formed by the combination of silver, Ag^{+} which is a metal and sulfur, S^{2-} which is a non-metal. Thus, it will form an ionic compound.

Option E:  N_2Cl_4

Nitrogen and chlorine, both are non-metals and they will form a covalent compound.

Option F:  Co(NO_3)_2

This compound is formed by the combination of cobalt, Co^{2+} which is a metal and NO_3^{-} ion which is a polyatomic ion. Thus, it will form an ionic compound.

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A change in matter that produces new substances is called a _____. 1.mixture 2.physical change 3.solution 4.chemical change
12345 [234]

Answer:

Chemical Change

Explanation:

chemical bonds within the substance have been altered because a new substance has been produced. It cannot be a mixture because they do not involve changes in matter, it cannot be a physical change because they do not result in new substances, it is not a solution because those do not involve changes in matter.

7 0
3 years ago
FILL IN THE BLANKWORD BANK (can use more than once): less, increases, decreases, greaterNO2Cl(g)+NO(g)⇌NOCl(g)+NO2(g)1.Disturbin
Jlenok [28]

Explanation:

If we have the following reaction at equilibrium:

<em>                                           aA + bB ⇄ cC + dD</em>

where a, b, c, and d are the stoichiometric coefficients for the reacting species A, B,  C, and D. For the reaction at a particular temperature:

                       Kc=([C]^c *[D]^d)/([A]^a *[B]^b)

where Kc is the equilibrium constant, which holds that <em>for a reversible reaction at equilibrium  and a constant temperature, a certain ratio of reactant and product concentrations has  a constant value, Kc</em> (the equilibrium constant). Note that although the concentrations  may vary, as long as the reaction in in equilibrium and temperatura don't change, the value of <u>K remains constant.</u>

For reactions that have not reached equilibrium, we obtain the reaction quotient (Qc), instead of the equilibrium  constant <u>by substituting the initial concentrations into the equilibrium constant expression.</u>

                        Qc=([Co]^c *[Do]^d)/([Ao]^a *[Bo]^b)

To determine the direction in wich the net reaction will proceed to reach equilibrium, que compare the values of Qc and Kc.

  • Qc < Kc: To reach equilibrium, reactants must be converted to products (→)
  • Qc = Kc: The initial concentrations are equilibrium concentrations. The system in at equilibrium.
  • Qc > Kc: To reach equilibrium, products must be converted to reactants (←)

Solution:

We have the following reaction:

                             NO2Cl(g)+NO(g)⇌NOCl(g)+NO2(g)

So:

Kc=([NOCl]^1*[NO2]^1)/([NO2Cl]^1 *[NO]^1)

     =([NOCl][NO2])/([NO2Cl][NO])  

1. In the equation above, [NO2Cl] it's in the denominator, so if we increase it's numericall value by adding NO2Cl <u>decreases Qc  to a value less than Kc.</u>

<em>(From the chemical point of view, if we disturb the equilibrium adding NO2Cl (a reactant), to reach equilibrium again the system proceeds from left to right (→) consuming this reactant.)</em>

2. To reach a new state of equilibrium (<em>where Qc = Kc</em>), Qc therefore  increases wich means that the denominator of the expression for Qc  decreases <em>(in order to increase the denominator as mention above).</em>

3. To accomplish this, the concentration of reageants decreases <em>(reagents are being consumed), </em>and the concentration of prodcuts increases <em>(products are being formed).</em>

4 0
3 years ago
A Gas OCCUPIES 525ML AT A PRESSURE OF 85.0 kPa WHAT WOULD THE VOLUME OF THE GAS BE AT THE PRESSURE OF 65.0 kPa
german

Boyle's law of ideal gas: This law states that the volume of a gas is inversely proportional to its pressure at a constant temperature. Acc to this law we can write the relation of pressure and volume as:

PV=Constant

That means:

P_{1}V_{1}=P_{2}V_{2}

From that equation we can calculate Volume of gas at a certain pressure:

P₁=Initial pressure

V₁=Initial volume

P₂=Final pressure

V₂= Final volume

Here P₁, initial pressure is given as 85.0 kPa

V₁, initial volume is given as 525 mL

P₂, final pressure is 65.0 kPa

P_{1}V_{1}=P_{2}V_{2}

so,

V_{2}=85\times 525\div 65

=686 mL

Volume of gas will be 686 mL.

8 0
3 years ago
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4vir4ik [10]

Answer:

A. last  F first E second C thrid b foruth A five

Explanation:

5 0
3 years ago
Read 2 more answers
Ozone, o3, is a product in automobile exhaust by the reaction represented by the equation no2(g) + o2(g) --&gt; 3no(g) + o3(g).
svetoff [14.1K]

Answer: 2.1 g mass of ozone(O_{3}) is predicted to form from the reaction of 2.0 g NO_{2} in a car's exhaust and excess oxygen

Given information : Mass of NO_{2} = 2.0 g and O_{2} is in excess.

We need to calculate the mass of ozone (O_{3})

Mass of ozone(O_{3}) is calculated with the help of mass of NO_{2} using stoichiometry.

NO_{2} + O_{2}\rightarrow NO + O_{3}

Step 1 : Convert grams of NO_{2} to moles of NO_{2}.

Moles = \frac{Grams}{Molar mass}

Molar mass of NO_{2} = 46.0 g/mol

Moles = \frac{2.0g}{46.0\frac{g}{mol}}

Moles of NO_{2} = 0.043 mol

Step 2 : Find the moles of O_{3} using moles of NO_{2}.

Moles of O_{3} is calculated by using moles of NO_{2} with the help of mole ratio.

A mole ratio is ​the ratio between the amounts in moles of any two compounds involved in a chemical reaction. The mole ratio may be determined by examining the coefficients in front of formulas in a balanced chemical equation.

From the balanced chemical equation we can see that coefficient of NO_{2} is 1 and coefficient of O3 is 1 , so mole ratio of O_{3} to NO_{2} is 1:1

Moles of O_{3} = (0.043 mol NO_{2})\times \frac{(1 mol O_{3})}{(1 mol NO_{2})}

Moles of O_{3} = (0.043)\times \frac{(1 mol O_{3})}{(1)}

Moles of O_{3} = 0.043 mol

Step 3 : Convert moles of O_{3} to grams of O_{3}

Grams = Moles X Molar mass

Molar mass of O_{3} = 48.0 g/mol

Grams = (0.043 mol O_{3})\times (\frac{48 g O_{3}}{1 mol O_{3}})

Grams = (0.043)\times (\frac{48 g O_{3}}{1})

Grams = 2.1 g O_{3}

Note : The above three steps can also be done using a single step setup.

Grams of O_{3} = (2.0 gNO_{2})\times \frac{(1mol NO_{2})}{(46.0 g NO_{2})}\times \frac{(1 mol O_{3})}{(1 mol NO_{2})}\times \frac{(48.0 g O_{3})}{(1 mol O_{3})}

Grams of O_{3} = (2.0 )\times \frac{(1)}{(46.0 )}\times \frac{(1)}{(1)}\times \frac{(48.0 g O_{3})}{(1)}

Grams of O_{3} = 2.1 grams


4 0
3 years ago
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