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Zanzabum
3 years ago
11

Examples of man made objects that spread an impulse over a large amount of time

Physics
1 answer:
MrRa [10]3 years ago
5 0

Example of object that spread an impulse over a large amount of time: airbag

Explanation:

The impulse exerted on a body during a collision is defined as the product between the force exerted on the body and the duration of the collision:

I=F \Delta t

where

I is the impulse

F is the average force

\Delta t is the duration of the collision

Also, the impulse is equal to the change in momentum of the body:

I=\Delta p

Therefore

\Delta p = F \Delta t

Which can be rewritten as

F=\frac{\Delta p}{\Delta t}

Assuming that the change in momentum in the collision is constant, this means that the force exerted on the body is inversely proportional to the duration of the collision: therefore, the larger the time, the smaller the force exerted.

The purpose of the airbag is indeed to increase the duration of the collision, \Delta t: this way, the force experienced by the driver during a car accident will be smaller.

Learn more about impulse:

brainly.com/question/9484203

#LearnwithBrainly

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A bird is flying due east. Its distance from a tall building is given by x(t) = 28.0 m + (12.4 m/s)t – (0.0450 m/s3)t3. What is
Kruka [31]

Answer:

3.76 m/s

Explanation:

Instantaneous velocity: This can be defined as the velocity of an object in a non uniform motion. The S.I unit is m/s.

v' = dx(t)/dt..................... Equation 1

Where v' = instantaneous velocity, x = distance, t = time.

Given the expression,

x(t) = 28.0 m + (12.4 m/s)t - (0.0450 m/s³)t³

x(t) = 28 + 12.4t - 0.0450t³

Differentiating x(t) with respect to t.

dx(t)/dt = 12.4 - 0.135t²

dx(t)/dt = 12.4 - 0.135t²

When t = 8.00 s.

dx(t)/dt = 12.4 - 0.135(8)²

dx(t)/dt = 12.4 - 8.64

dx(t)/dt = 3.76 m/s.

Therefore,

v' = 3.76 m/s.

Hence, the instantaneous velocity = 3.76 m/s

8 0
3 years ago
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Murrr4er [49]

Explanation:

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A 0.20-kg object is attached to the end of an ideal horizontal spring that has a spring constant of 120 N/m. The simple harmonic
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Answer:

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Explanation:

Given mass of object =0.20 kg

spring constant = 120 n/m

maximum speed = 1.9 m/sec

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Angular velocity is given by \omega=\sqrt{\frac{k}{m}}  where k is spring constant and m is mass

So v_{max}=A\sqrt{\frac{k}{m}}

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3 0
3 years ago
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Answer:

2633.7 s

Explanation:

From the question,

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t = 4190×40(75-20)/3500

t = 9218000/3500

t = 2633.7 s

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