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GREYUIT [131]
3 years ago
9

Consider an isolated system, by which we mean a system free of external forces. If the sum of the particle energies in the syste

m increases by 147 joules, what must have been the change deltacapU in the system's potential energy?
Physics
1 answer:
Airida [17]3 years ago
5 0

Answer:

The system's potential energy is -147 J.

Explanation:

Given that,

Energy = 147 J

We know that,

System is isolated and it is free from external forces.

So, the work done by the external forces on the system should be equal to zero.

W=0

We need to calculate the system's potential energy

Using thermodynamics first equation

\Delta U=W-\Delta E

Put the value into the formula

\Delta U=0-147

\Delta U=-147\ J

Hence, The system's potential energy is -147 J.

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The block in the diagram below is AT REST. However, the tension in the cable is not the only thing holding the block back. Stati
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Answer:

The  tension in the rope is 229.37 N.

Explanation:

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From the free body diagram, consider the forces in the vertical direction perpendicular to inclined plane.

Forces acting are mg\cos \theta and normal N. Now, there is no motion in the direction perpendicular to the inclined plane. So,

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