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GREYUIT [131]
3 years ago
9

Consider an isolated system, by which we mean a system free of external forces. If the sum of the particle energies in the syste

m increases by 147 joules, what must have been the change deltacapU in the system's potential energy?
Physics
1 answer:
Airida [17]3 years ago
5 0

Answer:

The system's potential energy is -147 J.

Explanation:

Given that,

Energy = 147 J

We know that,

System is isolated and it is free from external forces.

So, the work done by the external forces on the system should be equal to zero.

W=0

We need to calculate the system's potential energy

Using thermodynamics first equation

\Delta U=W-\Delta E

Put the value into the formula

\Delta U=0-147

\Delta U=-147\ J

Hence, The system's potential energy is -147 J.

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