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3 years ago

Only the cool kids know this one hehe Stephen or Damon??? and why?

Physics

2 answers:

mario62 [17]3 years ago

7 0

Damonnnn lol

ofc damon

Allushta [10]3 years ago

5 0

Answer:

Damonnnnnn omg Damon is everything

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When the material in the mantle cools off near the surface then sinks

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3 years ago

A container has a 5m^3 volume capacity and weights 1500 N when empty and 47,000 N when filled with a liquid. What is the mass de

Helen [10]

Answer:

927.62 kg/m³ and 0.9275.

Explanation:

Density: This can be defined as the ratio of the mass of a body and its volume.

The S.I unit of density is kg/m³.

Mathematically, Density can be expressed as

D = m/v......................... Equation 1

Where D = density of the body, m = mass of the body,v = volume of the body

Also,

m = W/g.................... Equation 2

Where W = weight of the body, g = acceleration due to gravity.

Given: W = 47000 - 1500 = 45500 N, g = 9.81 m/s²

Substitute into equation 2,

m = 45500/9.81

m = 4638.12 kg.

Also given: v = 5 m³

Substitute into equation 1,

D = 4638.12/5

D = 927.62 kg/m³

Hence the mass density of the liquid = 927.62 kg/m³

Specific gravity: This is the ratio of the density of a body to the density pf water.

R.d = D/D'................................ Equation 3

Where R.d = specific gravity, D = density of the liquid, D' = density of water.

Given: D = 927.62 kg/m³, D' = 1000 kg/m³

Substitute into equation 3

R.d = 927.52/1000

R.d = 0.9275.

Hence the specific gravity of the liquid = 0.9275.

6 0

3 years ago

Which of these quantities is constant in uniform circular motion?

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The answer is A, speed

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3 years ago

A child uses her hand to measure the width of a table too. Her hand has a width of 6.9 cm at its widest points, and she finds th

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3 years ago

A 150 kg line backer sacks the 120 kg quarterback. With what force is the quarterback sacked if the line backer has an accelerat

Gekata [30.6K]

Answer:

The force required to move the quarterback with linebacker is <u>1215 N</u>

Explanation:

$\text { Mass of linebacker } \mathrm{m}_{2}=150 \mathrm{kg}$

$\text { Mass of quarterback } \mathrm{m}_{2}=120 \mathrm{kg}$

$\text { Moved at an acceleration }(a)=4.5 \mathrm{m} / \mathrm{s}^{2}$

Using Newton's second law, it is established that F = Ma

Where F is net force acting on the system, a is the acceleration and M is mass of the two object $\left(m_{1}+m_{2}\right)$

Now consider both $\mathrm{m}_{1} \text { and } \mathrm{m}_{2}$ as a system, so net force acting on the system is $\text { Force }=\left(m_{1}+m_{2}\right) a$

Substitute the given values in the above formula,

$\text { Force }=(150+120) \mathrm{kg} \times 4.5 \mathrm{m} / \mathrm{s}^{2}$

$\text { Force }=270 \mathrm{kg} \times 4.5 \mathrm{m} / \mathrm{s}^{2}$

Force = 1215 N

<u>1215 N </u>is the force required to move the quarterback with linebacker.

5 0

3 years ago