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jeyben [28]
3 years ago
8

A 2-kg ball falls from a table 2 meters off the ground. How fast will it be traveling just before it hits the ground?

Physics
1 answer:
nignag [31]3 years ago
6 0
It will be 3 mph ______
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What maximum force do you need to exert on a relaxed spring with a 1.2×104-n/m spring constant to stretch it 6.0 cm from its equ
Elena L [17]

Answer:

Maximum force will be equal to 720 N

Explanation:

We have given that spring constant k=1.2\times 10^4N/m

Maximum stretch of the spring x = 6 cm = 0.06 m

We have to find the maximum force on the spring

We know that spring force is given by

F=kx=1.2\times 10^4\times 0.06=720N

So the maximum force which is necessary to relaxed the spring will be eqaul to 720 N

6 0
4 years ago
What is the formation of a shadow?
katovenus [111]

Answer:

Shadows are formed when an opaque object or material is placed in the path of rays of light. The opaque material does not let the light pass through it. The light rays that go past the edges of the material make an outline for the shadow

Explanation:

7 0
3 years ago
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A chair of mass 15.0 kg is sitting on the horizontal floor; the floor is not frictionless. You push on the chair with a force of
Neko [114]

Answer: 185.5672566

Explanation:  The friction is not relevant

Normal reaction is the force perpendicular to the surface.

this force resists the downwards forces applied which are gravity and a component of the applied force.

7 0
3 years ago
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A 3.70 kg block moving 2.09 m/s right hits a 2.42 kg block moving 3.92 m/s left. Find the total momentum of the system.
Novosadov [1.4K]

Answer:

-1.7534 Kg.m/s

Explanation:

Momentum, p is a product of mass and velocity, expressed as p= mv where m is the mass and v is the velocity which is dependent on the direction. Taking left as negative and right as positive then the initial momentum will be

p=-2.42*3.92+(3.7*2.09)=-1.7534 Kg.m/s

5 0
3 years ago
In a local bar, a customer slides an empty beer mug down the counter for a refill. The height of the counter is 1.46 m. The mug
Tresset [83]

Answer:

(a). The horizontal velocity is 1.46 m/s.

(b). The direction of the mug's velocity just before it hit the floor is 74.7° below the horizontal.

Explanation:

Given that,

Height of the counter = 1.46 m

Distance = 0.80 m

We need to calculate the time

Using equation of motion

s_{y}=ut+\dfrac{1}{2}gt^2

s_{y}=\dfrac{1}{2}gt^2

Put the value into the formula

1.46=\dfrac{1}{2}\times9.8\times t^2

t^2=\dfrac{1.46\times 2}{9.8}

t=\sqrt{\dfrac{1.46\times2}{9.8}}

t=0.545\ sec

Here, horizontal velocity is constant

(a). We need to calculate the velocity

Using formula of velocity

v_{x}=\dfrac{d}{t}

Put the value into the formula

v_{x}=\dfrac{0.80}{0.545}

v_{x}=1.46\ m/s

(b). We need to calculate the final velocity

Using equation of motion

v_{f}^2=u^2+2as

Put the value into the formula

v_{f}^2=0+2\times9.8\times1.46

v_{f}=\sqrt{28.616}

v_{f}=5.34\ m/s

The velocity is 5.34 m/s downward.

We need to calculate the direction

Using formula of direction

\tan\theta=\dfrac{v_{y}}{v_{x}}

\theta=\tan^{-1}(\dfrac{5.34}{1.46})

\theta=74.7^{\circ}

Hence, (a). The horizontal velocity is 1.46 m/s.

(b). The direction of the mug's velocity just before it hit the floor is 74.7° below the horizontal.

5 0
4 years ago
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