1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dem82 [27]
3 years ago
9

A 150 kg line backer sacks the 120 kg quarterback. With what force is the quarterback sacked if the line backer has an accelerat

ion of 4.5 m/s squared
Physics
1 answer:
Gekata [30.6K]3 years ago
5 0

Answer:

The force required to move the quarterback with linebacker is <u>1215 N</u>

Explanation:

\text { Mass of linebacker } \mathrm{m}_{2}=150 \mathrm{kg}

\text { Mass of quarterback } \mathrm{m}_{2}=120 \mathrm{kg}

\text { Moved at an acceleration }(a)=4.5 \mathrm{m} / \mathrm{s}^{2}

Using Newton's second law, it is established that  F = Ma

Where F is net force acting on the system, a is the acceleration and M is mass of the two object \left(m_{1}+m_{2}\right)

Now consider both \mathrm{m}_{1} \text { and } \mathrm{m}_{2}as a system, so net force acting on the system is \text { Force }=\left(m_{1}+m_{2}\right) a

Substitute the given values in the above formula,

\text { Force }=(150+120) \mathrm{kg} \times 4.5 \mathrm{m} / \mathrm{s}^{2}

\text { Force }=270 \mathrm{kg} \times 4.5 \mathrm{m} / \mathrm{s}^{2}

Force = 1215 N

<u>1215 N </u>is the force required to move the quarterback with linebacker.

You might be interested in
Allyson and Adrian have decided to connect their ankles with a bungee cord; one end is tied to each person's ankle. The cord is
Damm [24]

Complete question is;

Allyson and Adrian have decided to connect their ankles with a bungee cord; one end is tied to each person's ankle. The cord is 40 feet long, but can stretch up to 120 feet. They both start from the same location. Allyson moves 10 ft/sec and Adrian moves 9 ft/sec in the directions indicated. Adrian stops moving at time t = 5.5 sec, but Allyson keeps on moving 10 ft/sec in the indicated direction. (If a coordinate system is used, assume that the girls' starting position is located at

(x, y) = (0, 0) and that Allyson and Adrian move in the positive y and negative x directions, respectively. Let one unit equal one foot.)

Compute the length of the bungee cord at t = 7 seconds. (Round your answer to three decimal places.)

Answer:

Length of bungee cord = 85.734 ft

Explanation:

We are told that Adrian moves 9ft/sec. Thus, at 5.5 seconds, distance he moved is; 9 ft/sec × 5.5sec = 49.5 ft in the negative x (-x) direction. Therefore, the coordinate is (-49.5, 0).

Now, Allyson has moved 10ft/sec. Thus, at 7 seconds, distance he moved would be; 10 ft/sec x 7sec = 70 feet in the positive (+y) direction. Therefore, the coordinate is (0, 70).

Now, since they started from the origin, it means (0, 0) is a coordinate. Thus, we now have 3 coordinates which are; (0, 0), (0, 70) & (-49.5,0). These 3 coordinates would therefore combine to form a right triangle.

The hypotenuse is the distance between Allyson and Adrian.

Thus, from pythagoras theorem, we can find the distance between them which is same as the length of the cord.

Thus;

(-49.5)² + 70² = D².

D² = 2450.25 + 4900

D = √7350.25

D = 85.734 ft

4 0
3 years ago
A wagon wheel consists of 8 spokes of uniform diamter, each of mass m, and length L. The outer ring has a mass m rin. What is th
Genrish500 [490]

Answer:

L^2(\dfrac{8m}{3}+m_r)

Explanation:

m = Mass of each rod

L = Length of rod = Radius of ring

m_r = Mass of ring

Moment of inertia of a spoke

\dfrac{mL^2}{3}

For 8 spokes

8\dfrac{mL^2}{3}

Moment of inertia of ring

m_rL^2

Total moment of inertia

8\dfrac{mL^2}{3}+m_rL^2\\\Rightarrow L^2(\dfrac{8m}{3}+m_r)

The moment of inertia of the wheel through an axis through the center and perpendicular to the plane of the ring is L^2(\dfrac{8m}{3}+m_r).

3 0
3 years ago
This is the last question
koban [17]

Answer:

It's C

Explanation:

3 0
3 years ago
Can someone please solve this
Zina [86]

Answer:

The gravity is pulling the diver downwards but the rotation of the body means gravity cant pull him down as quickly

Explanation:

8 0
3 years ago
Calculate the east component of a resultant 32.5 m/s, 35.0° east of north.
ValentinkaMS [17]

Answer:

East component is: 18.64 m/s

Explanation:

If the resultant is 32.5 m/s directed 35 degrees east of north, then we use the sin(35) projection to find the east component of the velocity:

East component = 32.5 m/s * sin(35) = 18.64 m/s

4 0
3 years ago
Other questions:
  • You perform a double‑slit experiment in order to measure the wavelength of the new laser that you received for your birthday. Yo
    13·1 answer
  • A second baseman tosses the ball to the first baseman, who catches it at the same level from which it was thrown. The throw is m
    11·1 answer
  • The density of the object on the left is 1.5 g/cm3 and the density of the fluid is 1.0 g/cm3. Which has greater density? The obj
    8·2 answers
  • A student is on a skateboard facing a wall. The student and skateboard have a mass of 75 kilograms. The student pushes off of th
    11·1 answer
  • A ring of charge with uniform charge density is completely enclosed in a hollow donut shape. An exact copy of the ring is comple
    10·1 answer
  • Which of the following statements about a metal wire in the steady state are true? Select all that apply.
    12·1 answer
  • 2 strings both vibrate at exactly 220 Hz. The tension in one of them is then decreased sightly. As a result, 3 beats per second
    14·1 answer
  • How much current is drawn by a computer with a resistance of 42Ω that is connected across a potential difference of 220 V?
    6·2 answers
  • Why do ice cubes float to the top of a glass of water?
    8·2 answers
  • How does water form in the clouds? Explain how
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!