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3 years ago

What are some different ways large or small distance can be measured?

Chemistry

1 answer:

Lina20 [59]3 years ago

3 0

Answer:

The method used for measuring the small distance is by using the scales and the distance measured over long distance is by inch tape or measuring tape.

Explanation:

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Given that a chlorine-oxygen bond has an enthalpy of 243 kJ/mol , an oxygen-oxygen bond has an enthalpy of 498 kJ/mol , and the

Alecsey [184]

Explanation:

The chemical equation is as follows.

$\frac{1}{2}Cl_{2}(g) + \frac{1}{2}O_{2}(g) \rightarrow ClO(g)$

And, the given enthalpy is as follows.

$\frac{1}{2}Cl_{2}(g) + O_{2}(g) \rightarrow ClO_{2}(g)$ ; $\Delta H$ = 102.5 kJ

Cl-Cl = 243 kJ/mol, O=O = 498 kJ/mol

Since, the bond enthalpy of Cl-Cl is not given so at first, we will calculate the value of Cl-Cl as follows.

$\Delta H = \sum \text{bond broken in reactants} - \sum \text{bond broken in products}$

102.5 = $[(\frac{1}{2})x + 498] - [(2)(243)]$

102.5 = $(\frac{1}{2})x + 498 - 486$

102.5 - 12 = $\frac{x}{2}$

x = 181 kJ

Now, total bond enthalpy of per mole of ClO is calculated as follows.

$\Delta H = \sum E(\text{bond broken in reactants}) - \sum (\text{bond broken in products})$

x = $[(\frac{1}{2})181 + (\frac{1}{2})498] - 243$

= 339.5 - 243

= 96.5 kJ

Thus, we can conclude that the value for the enthalpy of formation per mole of ClO(g) is 96.5 kJ.

8 0

3 years ago

How many moles are in 1.84x10^24 formula units of CaCl2, calcium chloride?

Lady_Fox [76]

1 mole = 6.022 * 10^23 formula units.

1.84*10^24 formula units CaCl₂ * (1 mole CaCl₂/6.022*10^23 formula units CaCl₂) = 3.06 moles of CaCl₂.

There are 3.06 moles of CaCl₂.

7 0

3 years ago

How many valence electrons does p3- have

vazorg [7]

Answer: 8 valence electrons

Explanation:

7 0

3 years ago

A change in temperature is called a temperature _______________?

RUDIKE [14]

A change in temperature is called a temperature change

3 0