I'm pretty sure the answer is 1. I and III
<u>Answer:</u> There are
ammonium ions and
sulfate ions in the given amount of ammonium sulfate.
<u>Explanation:</u>
We are given 0.270 moles of ammonium sulfate and we need to find the number of ammonium and sulfate ions in it. The equation for the ionization of ammonium sulfate is given by the reaction:

By Stoichiometry,
1 mole of ammonium ions dissociates into 2 moles of ammonium ions and 1 mole of sulfate ion.
According to the mole concept:
1 mole of an ionic compound contains
number of ions.
Hence, 0.270 mole of ammonium sulfate will contain
number of ammonium ions and
number of sulfate ions.
Hence, there are
ammonium ions and
sulfate ions in the given amount of ammonium sulfate.
Explanation:
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<span>Electronegativity tends to increase from left to right across a row, because </span>the attraction between the nucleus and the valence electrons increases.
Answer:
Group 17 elements:
Flourine (F), Chlorine (Cl), Bromine (Br), Iodine (I), and Astatine (As).
Period 2 elements:
Lithium (Li), Beryllium (Be), Boron (B), carbon (C), Nitrogen (N), Oxygen (O), flourine (F), And Neon.