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3 years ago

Bases dissolve _ and _. 1. sugars 2. fats 3. oils or 4. proteins

1 answer:

6 0

Answer:due to principle "like dissolve like" as base is electronegativty it may dissolve with protein at it's isoelectronic point

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What is the new concentration of 25.0mL added to 125.0mL of 0.150M

____ [38]

Answer:

The new concentration is 0.125 M.

Explanation:

Given data:

Initial volume V₁ = 125.0 mL

Initial molarity M₁ = 0.150 M

New volume V₂ = 25 mL +125 mL = 150 mL

New concentration M₂ = ?

Solution:

M₁V₁ = M₂V₂

0.150 M × 125 mL = M₂ × 150 mL

M₂ = 0.150 M × 125 mL / 150mL

M₂ = 18.75 M.mL/150 mL

M₂ = 0.125 M

The new concentration is 0.125 M.

8 0

3 years ago

The concentration of reactants and products and the rate of reaction were measured during a chemical reaction. After the first 3

igomit [66]

Answer: B

Explanation:

4 0

1 year ago

I need the answers to those 2 :) don’t explain just answer :D

Gwar [14]

Answer:

where is the question?

Explanation:

4 0

2 years ago

An ideal gas sealed in a rigid 4.86-L cylinder, initially at pressure Pi=10.90 atm, is cooled until the pressure in the cylinder

seraphim [82]

Answer:

$\Delta H=-11897J$

Explanation:

Hello,

In this case, it is widely known that for isochoric processes, the change in the enthalpy is computed by:

$\Delta H=\Delta U+V\Delta P$

Whereas the change in the internal energy is computed by:

$\Delta U=nCv\Delta T$

So we compute the initial and final temperatures for one mole of the ideal gas:

$T_1= \frac{P_1V}{nR}=\frac{10.90atm*4.86L}{0.082*n}=\frac{646.02K }{n} \\\\T_2= \frac{P_2V}{nR}=\frac{1.24atm*4.86L}{0.082*n}=\frac{73.49K }{n}$

Next, the change in the internal energy, since the volume-constant specific heat could be assumed as ³/₂R:

$\Delta U=1mol*\frac{3}{2} (8.314\frac{J}{mol*K} )*(73.49K-646.02K )=-7140J$

Then, the volume-pressure product in Joules:

$V\Delta P=4.86L*\frac{1m^3}{1000L} *(1.24atm-10.90atm)*\frac{101325Pa}{1atm} \\\\V\Delta P=-4756.96J$

Finally, the change in the enthalpy for the process:

$\Delta H=-7140J-4757J\\\\\Delta H=-11897J$

Best regards.

7 0

3 years ago

Sometimes a nuclide is referenced by the name of the element followed by the:

pentagon [3]

Answer:

electric charge

Explanation:

A nuclide is represented by the name of the element, preceded by the mass number (A) as a superscript on the left and the atomic number (Z) as subscript.

On the right, as a superscript is the electrical charge (e.g. +2) and is following the element name.

8 0

3 years ago

Bases dissolve _____ and _____. 1. sugars 2. fats 3. oils or 4. proteins

Bases dissolve _ and _. 1. sugars 2. fats 3. oils or 4. proteins