As a horse finishes its trot around the corral, it slows from 4m/s to a stop in 3
seconds. Calculate the acceleration of the horse.
Can anybody help ?
Answer:
The ideas resemble their causes are the ideas of: Primary qualities: texture, number, size, shape, motion.
Explanation:
Answer:
0.35 T
Explanation:
Side, a = 0.132 m, e = 27.1 mV = 0.0271 V, dA / dt = 0.0785 m^2 / s
Use the Faraday's law of electromagnetic induction
e = rate of change of magnetic flux
Let b be the strength of magnetic field.
e = dФ / dt
e = d ( B A) / dt
e = B x dA / dt
0.0271 = B x 0.0785
B = 0.35 T
south = -(north)
Displacement = (4 km north) + (2 km south) + (5 km north) + (5 km south)
Displacement = (4 km north) - (2 km north) + (5 km north) - (5 km north)
Displacement = (4 - 2 + 5 - 5) km north
<u>Displacement = 2 km north </u>
