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Jet001 [13]
3 years ago
14

A planet orbits a star in an elliptical orbit. At a particular instant the momentum of the planet is <-3.9 x 10^29, -1.6 x 10

^29, 0> kg*m/s, and the force on the planet by the star is <-3.3 x 10^22, -1.9 x 10^23, 0> N. Find FlI and FI_ (Express your answers in vector form.)

Physics
1 answer:
Blizzard [7]3 years ago
6 0

Answer:

Solution is the following attachments

Explanation:

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I'm not sure but I think it's 35-39

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A girl pushes a 1.04 kg book across a table with a horizontal applied force 10 points
mr Goodwill [35]

Answer:

Approximately 11.0\; \rm m \cdot s^{-1}. (Assuming that g = 9.81 \; \rm N \cdot kg^{-1}, and that the tabletop is level.)

Explanation:

Weight of the book:

W = m \cdot g = 1.04 \; \rm kg \times 9.81\; \rm N \cdot kg^{-1} \approx 10.202\; \rm N.

If the tabletop is level, the normal force on the book will be equal (in magnitude) to weight of the book. Hence, F(\text{normal force}) \approx 10.202\; \rm N.

As a side note, the F_N and W on this book are not equal- these two forces are equal in size but point in the opposite directions.

When the book is moving, the friction F(\text{kinetic friction}) on it will be equal to

  • \mu_{\rm k}, the coefficient of kinetic friction, times
  • F(\text{normal force}), the normal force that's acting on it.

That is:

\begin{aligned}& F(\text{kinetic friction}) \\ &= \mu_{\rm k}\cdot F(\text{normal force})\\ &\approx 0.35 \times 10.202\; \rm N \approx 3.5708\; \rm N\end{aligned}.

Friction acts in the opposite direction of the object's motion. The friction here should act in the opposite direction of that 15.0\; \rm N applied force. The net force on the book shall be:

\begin{aligned}& F(\text{net force})  \\ &= 15.0 \; \rm N - F(\text{kinetic friction}) \\& \approx 15.0 - 3.5708\; \rm N \approx 11.429\; \rm N\end{aligned}.

Apply Newton's Second Law to find the acceleration of this book:

\displaystyle a = \frac{F(\text{net force})}{m} \approx \frac{11.429\; \rm N}{1.04\; \rm kg} \approx 11.0\; \rm m \cdot s^{-2}.

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A right triangle ABC has sides /AB/ =9cm, /BC/=12cm find /AC/ and angles ACB and ABC if angle BAC= 90°​
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8 0
3 years ago
Your house is 45.0 m from a powerline carrying 152 A of current. How much magnetic field does the current create at your house?
Sedaia [141]

This question involves the concepts of th magnetic field and current.

The magnetic field created by the current at the house is "6.75 x 10⁻⁷ T".

<h3>Magnetic Field</h3>

The magnetic field created by a current carrying wire can be given by the following formula:

B=\frac{\mu_o I}{2\pi r}

where,

  • B = magnetic field = ?
  • \mu_o= permeabiliy of free space =4π x 10⁻⁷
  • I = current = 152 A
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B=\frac{4\pi x\ 10^{-7}(152)}{2\pi(45)}

B = 6.75 x 10⁻⁷ T

Learn more about magnetic field here:

brainly.com/question/23096032

#SPJ1

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