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Olenka [21]
3 years ago
8

What types of energy are produced during firework displays?

Physics
2 answers:
-Dominant- [34]3 years ago
8 0

Answer: The chemical energy is converted to heat, light ,sound and kinematic movements.

Explanation:

An exploding firework is essentially a number of chemical reactions happening simultaneously or in rapid sequence. When you add some heat, you provide enough activation energy (the energy that kick-starts a chemical reaction) to make solid chemical compounds packed inside the firework combust (burn) with oxygen in the air and convert themselves into other chemicals, releasing smoke and exhaust gases such as carbon dioxide, carbon monoxide, and nitrogen in the process. For example, this is an example of one of the chemical reactions that might happen when the main gunpowder charge burn.

some of the chemical energylocked inside them is converted into four other kinds of energy (heat, light, sound, and the kinetic energy of movement). According to a basic law of physics called the conservation of energy.

bekas [8.4K]3 years ago
8 0

Answer:

Heat, Light and Sound.

Explanation:

There are 3 forms of energy generated by fireworks. They are:

Sound: Some fireworks produce a crackling sound while others creating an explosive sound.

Light: When fireworks explode, we see a bright light emitted from the explosion.

Heat: The explosive sound heard from fireworks are due to a quick release of energy at the surface of the fireworks.

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In which of the following conditions would there be the most resistance?
Natasha2012 [34]

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A) A warm wire

Explanation:

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3 years ago
Conservation of energy is explained as a scientific law and not a _______ because it does not explain why energy is conserved
AURORKA [14]

Answer:

Theory

Explanation:

Conservation of energy is explained as a scientific law and not a theory because it does not explain why energy is conserved.

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6 0
3 years ago
How much heat must be removed from 200 pounds of blanched vegetables at 189 degrees F to freeze them to a temperature of 22 degr
Virty [35]

To solve this problem it is necessary to apply the concepts related to heat exchange in the vegetable and water.

By definition the exchange of heat is given by

Q =mc\Delta T

where,

m = mass

c = specific heat

\Delta T = Change in temperature

Therefore the total heat exchange is given as

\Delta Q = Q_w+Q_v

\Delta Q = m_wc_w(T_i-T_f)+m_vc_v(T_i-T_f)

Our values are given as,

Total mass is M_T = 200lb ,however the mass of solid vegetable and water is given as,

m_v= 0.4*200lb = 80lb

m_w=0.6*200lb=120lb

T_i = 183\°F\\T_f = 22\°F\\c_w = 1Btu/lbF\\c_v = 0.24Btu/lbF

Replacing at our equation we have,

\Delta Q = m_wc_w(T_i-T_f)+m_vc_v(T_i-T_f)

\Delta Q = (120)(1)(183-22)+(80)(0.24)(183-22)

\Delta Q = 22411.2Btu

Therefore the heat removed is 22411.2 Btu

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3 years ago
A student performs an experiment in which a 4kg object travels across a horizontal surface with an initial speed velocity of 6m/
Snezhnost [94]

Answer:

The velocity of the center of mass of the two-object system remains constant during the experiment.

5 0
3 years ago
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