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erma4kov [3.2K]
3 years ago
13

I need help on this question

Mathematics
2 answers:
s344n2d4d5 [400]3 years ago
7 0
Answer one would be the correct answer-3
Paha777 [63]3 years ago
4 0

Answer:

a3

Step-by-step explanation:

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Read 2 more answers
Two cables support a 800​-lb ​weight, as shown. Find the tension in each cable.
jeka94

Answer:

  • 892 lb (right)
  • 653 lb (left)

Step-by-step explanation:

The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...

  Rcos(45°) +Lcos(75°) = 800

  Rsin(45°) -Lsin(75°) = 0

Solving these equations by Cramer's Rule, we get ...

  R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))

     = 800sin(75°)/sin(120°) ≈ 892 . . . pounds

  L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds

The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.

_____

This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...

  (right, left) = w/sin(α+β)×(sin(β), sin(α))

5 0
3 years ago
PLEASEEE HELP ITS SUOER EASY IM JUST IM NOT SMART
frozen [14]

Answer:

x must equal 0 or - 10

and y must equal 1 or 6

so its 3 x 0 = 0 plus 6 x 1 = 6

or 3 x -10 = -30 plus 6 x 6 = 36 so -30 plus 36 is 6

Step-by-step explanation:

3 0
2 years ago
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