Parallel lines refers to a pair of straight lines that never intercept or touch each other. The slopes of this lines is the same one.
On this exercise is given the equation of a line, and is asked to find the slope of a line that is parallel to the given one.
5x-3y=1 Subtract 5x in both sides
-3y=-5x+1 Divide by -3 in both sides to isolate y
y=5/3x-1/3
The slope of the given line, 5x-3y=1, is 5/3, which means that the slope of a line parallel to this one, would be 5/3.
56°
it goes up by 2 each small line
Answer:
Aircraft carrier speed = 4.97 km/h
Step-by-step explanation:
Given that the time taken by the aircraft = 5 hours
Let the distance covered = X
Speed = V
Time taken by the ship = 7 hours
Let the distance covered = Y
Speed = 8V
Since it is 8 km/h faster than the aircraft carrier.
Using the speed formula
Speed = distance/time
Distance = speed × time
For the aircraft;
X = 5V
For the ship:
Y = 7 × 8V = 56V
Since they are 303km distance apart,
X + Y = 303
5V + 56V = 303
61V = 303
V = 303/61
V = 4.97 km/h
Aircraft carrier speed = 4.97 km/h
The fraction of this decimal is 1/5
First of all you need to find the coordinates of each points in the graph. Second is to find the slope or the rise over run of the graph when it is connected to every points. The third is to apply the formula in solving the function by assigning each value. The formula is Y=MX+B
