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3 years ago

Particles are measured in

Chemistry

2 answers:

vladimir1956 [14]3 years ago

5 0

Particles are measured in atomic mass units, or AMU.

cluponka [151]3 years ago

4 0

Atomic mass units also abbreviated to AMU's

You might be interested in

The atomic mass of a atom (in amu) is equal to

kobusy [5.1K]

1.67377x10-27 kilogram(kg) or 1.67377x 10-24 gram(g)

5 0

3 years ago

Read 2 more answers

If you get some of the right sort of organic material, and heat it in the right sort of way, perhaps with a little squeezing, yo

AnnZ [28]

Question Options:

A) Bituminous, peat, lignite, anthracite.

B) Anthracite, bituminous, lignite, peat.

C) Peat, anthracite, lignite, bituminous.

D) Peat, lignite, bituminous, anthracite.

E) Bituminous, peat, anthracite, lignite.

Answer: Anthracite, bituminous, lignite, peat.

Explanation:

Anthracite is a form of carbonized ancient plants; the hardest and cleanest-burning of all the coals.

Bituminous is a form of coal that is characterized by mineral pitch; a black, tarry substance, burning with a bright flame.

Lignite is a low grade brownish coal.

Peat is a form of coal formed of dead but not fully decayed plants found in bog areas, often burned as fuel.

From the definitions given above, one can categorically say the most heated is in a descending order. And According to the Question, most heated is most valuable.

3 0

3 years ago

IM GIVING 30 POINTS PLUS BRAINLIEST FOR CORRECT ANSWERS !!!

ELEN [110]

Answer:

The answer to your question is:

Explanation:

3.- Convert each into

1.56 x 10⁴ = 15600

0.00259 x 10⁵ = 259

0.00259 x 10³ = 2.59

0.56 x 10⁻² = 0.0056

0.000459 x 10⁻¹ = 0.0000459

0.0209 x 10⁻³ = 0.0000209

3.69 x 10⁻² = 0.0369

13.69 x 10⁻² = 0.1369

736.9 x 10⁵ = 73690000

6.9 x 10⁴ = 69000

4.- Calculate the following

a) 2653000 = 2.653 x 10⁶

b) -2687 = - 2.687 x 10³

c) 2.532 x 10²⁴

d) 1470 = 1.47 x 10³

7 0

3 years ago

Read 2 more answers

How fast is an electron travelling If it has a wavelength of 8.20 km?

Lemur [1.5K]

The electron is travelling with a velocity of 1.123 × 10⁷m/s if it has a wavelength of 8.20 km.

<h3>How to calculate velocity of an electron?</h3>

The velocity at which an electron travels can be calculated using the following formula:

λ = h/mv

Where;

H = Planck's constant
m = mass of electron
v = velocity of electron
λ = wavelength

Planck's constant (h) = 6.626 × 10−³⁴ J⋅s.
mass of electron (m) = 9.109 × 10−³¹ kg
wavelength = 8200m

8200 = 6.626×10−³⁴ / 9.109 × 10−³¹V

8200 = 7.3 × 10-⁴V

V = 8200 ÷ 7.3 × 10-⁴

V = 1.123 × 10⁷m/s

Therefore, the electron is travelling with a velocity of 1.123 × 10⁷m/s if it has a wavelength of 8.20 km.

Learn more about velocity at: brainly.com/question/13171879

#SPJ1

5 0

2 years ago

Calculate the mass of iron(III) oxide that contains a million iron atoms. Be sure your answer has a unit symbol if necessary, an

KiRa [710]

<u>Answer:</u> The mass of iron (II) oxide that contains a million iron atoms is $2.6\times 10^{-17}g$

<u>Explanation:</u>

We are given:

Number of iron atoms = A million = $1.0\times 10^6$

The chemical formula of the given compound is $Fe_2O_3$

It is formed by the combination of 2 iron atoms and 3 oxygen atoms.

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of particles

1 mole of iron (II) oxide will contain = $(2\times 6.022\times 10^{23})=1.2044\times 10^{24}$ number of iron atoms

We know that:

Molar mass of iron (II) oxide = 159.7 g/mol

Applying unitary method:

For $1.2044\times 10^{24}$ number of iron atoms, the mass of iron (II) oxide is 159.7 g

So, for $1.0\times 10^6$ number of iron atoms, the mass of iron (II) oxide will be $\frac{159.7}{1.2044\times 10^{24}}\times 1.0\times 10^6=2.6\times 10^{-17}g$

Hence, the mass of iron (II) oxide that contains a million iron atoms is $2.6\times 10^{-17}g$

8 0

4 years ago