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Len [333]
3 years ago
8

At standard pressure, the total amount of heat required to completely vaporize a 100. gram sample of water at its boiling point

is(1) 2.26 X 10 J (3) 2.26 X 103 J
(2) 2.26 X 102 J (4) 2.26 X 105 J
Chemistry
1 answer:
zvonat [6]3 years ago
4 0
We know that the heat of vaporization of water is 2260 J/g. So 100 gram sample of water being completely vaporized needs 2260*100=2.26*10^5 J. So the answer is (4).
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Copper(II) sulfide is oxidized b molecular oxygen to produce gaseous sulfur trioxide and solid copper (II) oxide. The gaseous pr
Tasya [4]

Explanation:

Copper(II) sulfide reacts with oxygen gas to give solid copper(II) oxide and sulfur trioxide gas.

The reaction is given as:

CuS+2O_2\rightarrow CuO(s)+SO_3(g)

When 1 mol copper(II) sulfide react with 2 moles of oxygen gas it gives 1 mol of solid copper(II) oxide and 1 mol of sulfur trioxide gas

The gas formed in above reaction that is sulfur trioxide reacts with water to give sulfuric acid or hydrogen sulfate.

The reaction is given as:

SO_3(g)+H_2O(l)\rightarrow H_2SO_4(aq)

1 mol of sulfur trioxide gas reacts with 1 mol of liquid water to produce 1 molo of liquid hydrogen sulfate or sulfuric acid

3 0
3 years ago
1. A gas expands and does p-v work on the surroundings equal to
azamat

The change in energy of the system : -63 J

<h3>Further explanation</h3>

Given

279 J work

216 J heat

Required

The change in energy

Solution

Laws of thermodynamics 1

ΔU=Q+W

Rules :

  • receives heat, Q +  
  • releases heat, Q -  
  • work is done by a system, W -  
  • work is done on a system, W +  

a gas work on the surrounding : W =-279 J

a gas absorb heat from surrounding : Q = +216 J

Internal energy :

= -279+216

= -63 J

3 0
2 years ago
Fill in the blanks.
vichka [17]

Answer:

Hello There!!

Explanation:

1.C nH 2n

2.Family

3.carbonyl group

4.Catalyst

5.Nickel

hope this helps,have a great day!!

~Pinky~

4 0
3 years ago
Read 2 more answers
A solution is made by dissolving 58.125 g of sample of an unknown, nonelectrolyte compound in water. The mass of the solution is
e-lub [12.9K]

Answer:

molecular weight (Mb) = 0.42 g/mol

Explanation:

mass sample (solute) (wb) = 58.125 g

mass sln = 750.0 g = mass solute + mass solvent

∴ solute (b) unknown nonelectrolyte compound

∴ solvent (a): water

⇒ mb = mol solute/Kg solvent (nb/wa)

boiling point:

  • ΔT = K*mb = 100.220°C ≅ 373.22 K

∴ K water = 1.86 K.Kg/mol

⇒ Mb = ? (molecular weight) (wb/nb)

⇒ mb = ΔT / K

⇒ mb = (373.22 K) / (1.86 K.Kg/mol)

⇒ mb = 200.656 mol/Kg

∴ mass solvent = 750.0 g - 58.125 g = 691.875 g = 0.692 Kg

moles solute:

⇒ nb = (200.656 mol/Kg)*(0.692 Kg) = 138.83 mol solute

molecular weight:

⇒ Mb = (58.125 g)/(138.83 mol) = 0.42 g/mol

8 0
3 years ago
Which of the following best defines the term oxidation state?
eimsori [14]
C seems to be the best answer

4 0
3 years ago
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