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posledela
1 year ago
7

How many grams of agcl would be needed to make a 4. 0 m solution with a volume of 0. 75 l?

Chemistry
1 answer:
devlian [24]1 year ago
8 0

430 g of AgCl would be needed to make a 4.0m solution with a volume of 0.75 L.

<h3>What is Molarity?</h3>
  • The amount of a substance in a specific volume of solution is known as its molarity (M).
  • The number of moles of a solute per liter of a solution is known as molarity.
<h3>Calculation of Required amount of AgCl</h3>

Remember that mol/L is the unit of molarity (M).

We can compute the necessary number of moles of solute by multiplying the concentration by the liters of solution, according to dimensional analysis.

0.75L×4.0M=3.0mol

Then, using the periodic table's molar mass for AgCl, convert from moles to grams:

3.0mol×143.321gmol=429.963g

The final step is to round to the correct significant figure, which in this case is two: 430g.

Hence, 430 g of AgCl would be needed to make a 4.0m solution with a volume of 0.75 L.

Learn more about Molarity here:
brainly.com/question/8732513

#SPJ4

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Photosynthesizing plants and algae convert light energy into chemical energy, which then gets passed through the food web to plant eaters, flesh eaters, and ultimately to scavengers and decomposers.
8 0
3 years ago
Which statement is correct regarding the reaction ?
larisa86 [58]

The true statement is that after reaching equilibrium, the rate of forming products and reactants is the same.

<h3>What is true about the given reaction?</h3>

The given reaction shows a reaction between A and B to form CD

The reaction is a reversible reaction.

A reversible reaction is a reaction which can proceed in either of two ways where the reactants can react to form the product and also the products an break down to form the reactants.

In the reaction given, as the concentration of A and b decreases, the concentration of CD increases and vice versa.

At equilibrium, the rate of formation of CD is equal to the the rate of decomposition of CD.

Therefore, the true statement is that after reaching equilibrium, the rate of forming products and reactants is the same.

In conclusion, a reaction at equilibrium has the forward and backward reactions occurring at the sane rate.

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5 0
1 year ago
26. Balance the following equations:<br> Ca(s) + H3PO4(aq)Ca3(PO4)2(s) + H2(g)
yKpoI14uk [10]

Hey there!

Ca + H₃PO₄ → Ca₃(PO₄)₂ + H₂

Balance PO₄.

1 on the left, 2 on the right. Add a coefficient of 2 in front of H₃PO₄.

Ca + 2H₃PO₄ → Ca₃(PO₄)₂ + H₂

Balance H.

6 on the left, 2 on the right. Add a coefficient of 3 in front of H₂.

Ca + 2H₃PO₄ → Ca₃(PO₄)₂ + 3H₂

Balance Ca.

1 on the right, 3 on the right. Add a coefficient of 3 in front of Ca.

3Ca + 2H₃PO₄ → Ca₃(PO₄)₂ + 3H₂

Our final balanced equation:

3Ca + 2H₃PO₄ → Ca₃(PO₄)₂ + 3H₂

Hope this helps!

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3 years ago
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B) Morrison and Franscioni's research done to create the Frisbee. 
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Read 2 more answers
The tendency of an element to react is closely related to
Bad White [126]
C. The number of Valence electrons,
Every atom tries to follow the Octet rule i.e To have 8 electrons in its Valence shell.
Every atom tries to accomodate 8 electrons in its Valence shell to stabilize themselves, Metals usually have 1-3 eletrons in their Valence shell which they donate to non metals so their Valnce shell has 8 electroons, (The previous will now be the Valence shell and it will be full)
Similarly Non metals have 4-7 electrons, they accept electrons from metals so they can have 8 electrons in their Valence shell.
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Hope it helps :)

8 0
3 years ago
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