Answer: For example, the polynomial which can also be expressed as has three terms. The first term has a degree of 5 (the sum of the powers 2 and 3), the second term has a degree of 1, and the last term has a degree of 0. Therefore, the polynomial has a degree of 5, which is the highest degree of any term.
Step-by-step explanation: (If this helps)
Answer:
Degrees
Step-by-step explanation:
dont need one
Answer:
Step-by-step explanation:
<em>In a regular pentagon, all the angles and sides are equal. So, to find an angle, divide 540 by 5.</em>
Sum of all angles of regular pentagon = 540
measurement of one angle = 540 ÷ 5
= 108°
∠N = 108°
The average speed of blood in the aorta is 0.2833 m/s
Speed is the ratio of distance travelled to time taken. It is given by:
Speed = distance / time
From the question, to calculate the average speed:
Average speed = Volume rate / cross sectional area
Average speed = 8.5 * 10⁻⁵ / (3 * 10⁻⁴) = 0.2833 m/s
The average speed of blood in the aorta is 0.2833 m/s
Find out more on average speed at: brainly.com/question/680492
(1) ∠ABC = 65°, ∠DBE = 65°, ∠CBE = 115°, ∠ABD = 115°
(2) ∠ABC = 62°, ∠DBE = 62°, ∠CBE = 118°, ∠ABD = 118°
Solution:
(1) In the given image ABC and DBE are vertical angles.
<u>Vertical angle theorem:</u>
If two angles are vertical then they are congruent.
⇒ ∠ABC = ∠DBE
⇒ 3x° + 38° = 5x° + 20°
Arrange like terms one side.
⇒ 38° – 20° = 5x° – 3x°
⇒ 18° = 2x°
⇒ x° = 9°
∠ABC = 3(9°) + 38° = 65°
∠DBE = 5(9°) + 20° = 65°
Adjacent angles in a straight line = 180°
⇒ ∠ABC + ∠CBE = 180°
⇒ 65° + ∠CBE = 180°
⇒ ∠CBE = 115°
∠ABD and ∠CBE are vertical angles.
∠ABD = 115°
(2) In the given image ABC and DBE are vertical angles.
⇒ ∠ABC = ∠DBE
⇒ 4x° + 2° = 5x° – 13°
Arrange like terms one side.
⇒ 13° + 2° = 5x° – 4x°
⇒ 15° = x°
∠ABC = (4(15°) + 2°) = 62°
∠DBE = 5(15°) – 13° = 62°
Adjacent angles in a straight line = 180°
⇒ ∠ABC + ∠CBE = 180°
⇒ 62° + ∠CBE = 180°
⇒ ∠CBE = 118°
∠ABD and ∠CBE are vertical angles.
∠ABD = 118°
