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Taya2010 [7]
3 years ago
9

Write an integer for: a deposit of $45 * Plz help fast!

Mathematics
1 answer:
Mice21 [21]3 years ago
6 0

Answer:

$45

Step-by-step explanation:

  1. A deposit is positive, so the integer will be positive.
  2. An integer is a whole number that's not a fraction, so a positive integer for 45, would be 45.

I hope this helps!

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What is the irrational number in This set: 12.89, square root of 12 and 12/144 ?
kifflom [539]
Good night, 

<span>Irrational numbers are those that can't be expressed as a fraction:

12.89 can be expressed as: </span>\frac{1289}{100}

\frac{12}{144}= \frac{1}{12}

<span>The above numbers can be expressed as a fraction, then the logical answer is: </span>\sqrt{12}

But we will check the answer: 

\sqrt{12}= \sqrt{2^{2}*3 }  =2* \sqrt{3} =3.4641016...

As you can see we can't express that number as a fraction, so that is te correct answer.

6 0
3 years ago
Can someone help me!
Ganezh [65]
Looks to Be answer A have a great day!
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2 years ago
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blsea [12.9K]

Answer:

D

Step-by-step explanation:

30.20 * 15% (or 0.15) = 4.53

4.53 is about 4.50

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3 years ago
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Can someone please help me with this question​
bezimeni [28]

Answer:

21x^2-2x+1

Step-by-step explanation:

The area of shaded region= The area of the floor - area of the identical islands

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6 0
2 years ago
Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)
Dima020 [189]

Split C into two component segments, C_1 and C_2, parameterized by

\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)

\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)

respectively, with 0\le t\le1, where \mathbf r_i(t)=(x(t),y(t)).

We have

\mathrm d\mathbf r_1=(6,1)\,\mathrm dt

\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt

where \mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt

so the line integral becomes

\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)

=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt

=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6

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3 years ago
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