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2 years ago

Meredith has $630,000 she wants to save. If the FDIC insurance limit per

Mathematics

1 answer:

Viefleur [7K]2 years ago

3 0

Answer:

$200,000 in bank A, $200,000 in bank B, $230,000 in bank C

Step-by-step explanation:

Meredith has $630,000

Limit per depositor, per bank, is $250,000

She needs to distribute her money between three Banks to guarantee that her money is insured.

A. $200,000 in bank A, $200,000 in bank B, $230,000 in bank C

It can be seen in A that her deposit per bank deposit didn't exceed the $250,000 limit in the three Banks.

B. $200,000 in bank A, $170,000 in bank B, $260,000 in bank C

Here, her deposit in bank C exceeds $250,000, so there is no guarantee for insurance in bank C

C. $160,000 in bank A, $180,000 in bank B, $290,000 in bank C

Her deposit in bank C is $290,000 which exceeds the $250,000 limit. Therefore, no guarantee for insurance of her money in bank C

D. $160,000 in bank A, $200,000 in bank B, $270,000 in bank C

you

Also, her deposit in bank C exceeds $250,000, so there is no guarantee for insurance in bank C

The way her money can be distributed between three Banks and guarantee insurance is

A. $200,000 in bank A, $200,000 in bank B, $230,000 in bank C.

That way, her deposit per bank is less than the $250,000 limit

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Help please i really need it

mihalych1998 [28]

Answer:

3x - 4

Step-by-step explanation:

Slope (m): 3

Y-intercept (c): = -4

Equation of Line: Y=mx + c

Y=3x -4

3 0

3 years ago

solo savings bank received an initial deposit of $6000 it kept a percentage of this money in reserve based on the reserve rate a

iogann1982 [59]

Answer:

Reserve rate = 3%

Step-by-step explanation:

Reserve Ratio = Reserve Maintained with Central Bank / Deposit Liabilities × 100

Reserve maintained = $6,000

Deposit liabilities = $200,000

Reserve Rate = Reserve Maintained with Central Bank / Deposit Liabilities × 1000

=$6,000 / $200,000 × 100

=0.03 × 100

r=0.03 × 100

=3%

Therefore,

Reserve Rate =3%

8 0

3 years ago

N independent random samples of 10 men and 10 women in a coed basketball league, the numbers of points scored per season are giv

faltersainse [42]

Answer:

Step-by-step explanation:

Hello!

To compare both datasets I've made a box plot for them.

The yellow one belongs to the points scored by the men and the green one is for the points scored by the women.

Women: The box seems symmetrical, the median and the mean (black square) are almost the same. The whiskers are almost the same length, you could say that in general the points scored by the women have a symmetrical distribution.

Men: The box looks a little skewed to the right, the median is closer to the 1st quantile and the mean is greater than the median. The whiskers are the same length, in general the distribution seems almost symmetrical.

As you can see in the box plot the median and mean of the points scored by the women are almost the same. Using the data I've calculated both values:

Me= 24.50

X[bar]= 23.80

The median divides the sample in halves (50-50), it shows you where the middle of the distribution is.

The average shows you the value that centers the distribution, meaning, it is the value around which you'll find most of the data set. It summarizes best the sample information and therefore is a better measure of center.

As you can see in the box plots, there are no outliers in both distributions.

An outlier is an observation that is significantly distant from the rest of the data set. They usually represent experimental errors (such as a measurement) or atypical observations. Some statistical measurements, such as the sample mean, are severely affected by this type of values and their presence tends to cause misleading results on a statistical analysis.

Considering the 1st quartile (Q₁), the 3rd quartile (Q₃) and the interquartile range IQR, any value X is considered an outlier if:

X < Q₁ - 1.5 IQR

X > Q₃ + 1.5 IQR

Or extreme outliers if:

X < Q₁ - 3 IQR

X > Q₃ + 3 IQR

For the women data set:

Q₁= 17; Q₃= 30; IQR= 30 - 17= 13

Lower outliers: X < Q₁ - 1.5 IQR= 17-1.5*13= -2.5 ⇒ The minimum value recorded is 03, so there are no outliers.

Upper outliers: X > Q₃ + 3 IQR= 30 + 1.5*13= 49.5 ⇒ The maximum value registered is 41, so there are no outliers.

I hope this helps!

6 0

2 years ago

The function graphed above is:

dem82 [27]

Step-by-step explanation:

When the slope of the function is positive, it is increasing

when the slope of the function is negative, it is decreasing

just like with the line function y = mx + b

so if you put a line tangent to the function at every point the slope of the line will indicate a increasing or decreasing point of the function

also beware where the slope is zero it is not increasing or decreasing

there are two intervals of increasing, one interval of decreasing and two point of zero slope or neither increasing or decreasing

increasing interval 1) x < -2 2) x > 1.5

decreasing interval 1) -2 < x < 1.5

at -2 and 1.5 the slope is zero

5 0

2 years ago

Helpers are needed to prepare for the fete. Each helper can make either 2 large cakes per hour, or 35 small cakes per hour. The

amid [387]

If 20 large cakes are needed, you'll need 4 helpers. To find this, you first need to find how many cakes 1 helper can make. Every hour, one helper can make 2 large cakes. If they have the kitchen for 3 hours, 6 large cakes can be made by one helper. This also means that 2 helpers make 12 cakes, 3 helpers can make 18 cakes, and 4 helpers can make 24 cakes. Since you can't have a fraction of a helper, 4 is your answer. For the 700 small cakes, you do the same thing. Every hour, 1 helper makes 35 small cakes. In 3 hours, 1 helper can make 105 small cakes. 2 can make 210, 3 can make 315, 4 can make 420, 5 can make 525, 6 can make 630, and 7 can make 735. The 700 small cakes takes 7 helpers and the 20 large cakes takes 4 helpers. Your total amount of helpers is 11.

8 0

3 years ago