Since
Electric potential energy = qV
Where V = Ed
Hence
Electric potential energy = q(Ed) --- (1)
Since E = 1.0 * 10^3 N/C
d = 0.10 m
q = 4 * 10^-6 C
Plug in the values in (1)
(1) => Electric potential energy = 4 * 10^-6(1.0 * 10^3 * 0.10)
Electric potential energy = 400 μJ
There may be an improper voltage in the device.
<u>Explanation</u>:
- Given the device has unknown circuitry and the voltage across the device crosses the voltage across the resistor at 500 Hz. In this device, the current flow is not correct. It is improper.
- The elements in the device are ammeter, capacitor, inductor, voltmeter, and battery. The components in the device may not be connected properly. This is due to the improper flow of current and condition of the voltmeter.
- So these are the type of elements in the device.
Answer:
vi) Double the current in the wire, and double the number of turns in the 20-cm long solenoid
Explanation:
The magnetic field inside the solenoid and the current flowing in the coil of solenoid are related to each other by the following equation
B₀=μ₀nI₀
Where,
B₀ is the magnetic field in the middle of solenoid
n is the number of turns in the coil of solenoid
I₀ is the current flowing in the coil of solenoid
In the above equation, as μ₀ is a constant so the magnetic field will be directly proportional to the number of turns multiplied by the current. So, changing the radius of the coil or length of the coil will have no effect on the magnetic field.
As we have to increase the magnetic field by 4 times, we need to double the current as well as the number of turns as mentioned in the option vi.
It's called "utter disregard for the safety and welfare
of the people standing at the bottom of the hill".
